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Generate random numbers from 0 to 7 with every number appearing 2 times in java ADT


Generate random numbers from 0 to 7 with every number appearing 2 times in java ADT

By : Michael Allegrini
Date : November 21 2020, 07:31 AM
help you fix your problem A straightforward way is to do it with Collections.shuffle().
Pseudocode:
code :
for(0 to 7)
   myArrayList.add(num);
   myArrayList.add(num);
Collections.shuffle(myArrayList);

// Convert to array if necessary


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How to generate a random number with Java from given list of numbers

How to generate a random number with Java from given list of numbers


By : Rob Tickner
Date : March 29 2020, 07:55 AM
wish helps you Put the numbers in an ArrayList and use Collections.shuffle(arrayList);
How do i generate a random number but make sure its between a range of two numbers (JAVA)

How do i generate a random number but make sure its between a range of two numbers (JAVA)


By : Kristina S
Date : March 29 2020, 07:55 AM
I hope this helps . I need to generate a random number between 8 and 32. then multiply to the power of 2. then repeat it in a loop 10 times. I can't figure how to generate the number within a range this is what i have so far. , In plain english:
Math.random returns a number between 0 and 1.
code :
var random = Math.random();

var number1 = 5.0;
var number2 = 12;

var range = number2-number1;
var rangedRandom = range*random;

var rangedRandomPlusLeast = number1+rangedRandom;

var rangedRandomPlusLeastAsInteger = Math.round(rangedRandomPlusLeast); 
How to generate a list of distinct random numbers including a specific number in JAVA?

How to generate a list of distinct random numbers including a specific number in JAVA?


By : Hugo Gonçalves
Date : March 29 2020, 07:55 AM
will be helpful for those in need Ok, so the scenario is, I want to generate a list of 4 distinct random numbers which will represent 4 random choices for a quiz application. One of the 4 random choices will be the correct answer, so we will already know the index of the correct choice. This correct index or number must be included in the random number list. , For Java 6 and newer:
code :
final int maxNumber = 100;
final int numbersToGenerate = 4;
final int correctAnswer = 45;

Set<Integer> possibleAnswers = new HashSet<>();
Random random = new Random();

// add correct answer
possibleAnswers.add(correctAnswer);

// add as much random answers as needed, the usage of a set prevents duplicates
while(possibleAnswers.size() < numbersToGenerate) {
    possibleAnswers.add(random.nextInt(maxNumber));
}

// convert set to list and shuffle it
List<Integer> answers = new ArrayList<Integer>(possibleAnswers);
Collections.shuffle(answers, new Random(System.nanoTime()));
final int minNumber = 1;
final int maxNumber = 100;
final int numbersToGenerate = 3;

final int[] ints = new Random().ints(minNumber, maxNumber)
.distinct().limit(numbersToGenerate).toArray();

List<Integer> possibleAnswers = asList(ints);
possibleAnswers.add(correctAnswerIndex);
Collections.shuffle(possibleAnswers, new Random(System.nanoTime()));
JAVA - How do I generate a random number that is weighted towards certain numbers?

JAVA - How do I generate a random number that is weighted towards certain numbers?


By : Anvesh
Date : March 29 2020, 07:55 AM
wish help you to fix your issue How do I generate a random number in Java, (using Eclipse) that is weighted towards certain numbers?
code :
public static void main(String[] args){
    ArrayList<Integer> list = new ArrayList<Integer>();
    list.add(5);list.add(2);// to be continued ...        
    int randomInt = list.get((int) (Math.random() * list.size()));
    System.out.println(randomInt);
}
Generate random number bounded between two numbers in Java Card

Generate random number bounded between two numbers in Java Card


By : g.roman
Date : March 29 2020, 07:55 AM
this will help Note that I have only tested the distribution of the random numbers using SecureRandom within Java SE. I'm reasonably sure that this code is correct though. The code uses the "simple reject" method defined by NIST.
So without further ado, the code.
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