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Updating multiple id in Javascript


Updating multiple id in Javascript

By : Pat Garlock
Date : November 21 2020, 07:31 AM
should help you out id's can only be used once on the page. You can do this by using a class instead:
HTML
code :
<ul class="nav nav-pills">
   <li class="dropdown menu-btn">
      <a href="#" class="dropdown-toggle" data-toggle="dropdown" >
         <span class="glyphicon glyphicon-map-marker"></span> 
         <span class="update">San Francisco</span><b class="caret"></b>
      </a>
      <ul id="myCitylist" class="dropdown-menu">
        <li> <a href="#">San Jose</a> </li>
        <li> <a href="#">Silicon Valley</a> </li>
        <li> <a href="#">New York City</a> </li>
        <li> <a href="#">Paris</a> </li>
        <li> <a href="#">Silicon Valley</a> </li>
        <li> <a href="#">Tokyo</a> </li>
      </ul>
  </li>
</ul>

<div>Now we'll talk about <span class="update">San Francisco</span></div>
$('.dropdown-menu').on('click', "li", function(){
  var optionChosen = $(this).text();
  $(this).closest("ul.nav.nav-pills").find("span.update").text(optionChosen).end().next().find("span.update").text(optionChosen);  
 });


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Updating multiple array elements at once Javascript

Updating multiple array elements at once Javascript


By : user3819943
Date : March 29 2020, 07:55 AM
help you fix your problem FEtypes is an object, not an array. Push is only available on arrays.
If you want to store this structure in an array, it would look something like:
code :
var FEtypes= [
      {type :"Text", size : 50,  required : "no", FEadd  :'<input>', label : 'Label', top : 0, left : 0}, 
      {type : "Textarea", cols : 30,  rows : 5,FEadd :'<textarea>' }
];
FEtypes[1].left = someVariable1;
FEtypes[1].top = someVariable2;
$.extend(FEtypes[1], {left:someVariable1, top:someVariable2});
FEtypes.textareaTemplate.left = someVariable1;
FEtypes.textareaTemplate.top = someVariable2;
$.extend(FEtypes.textareaTemplate, {left:someVariable1, top:someVariable2});
Updating Multiple Select Values via Javascript

Updating Multiple Select Values via Javascript


By : Lian Chyn
Date : March 29 2020, 07:55 AM
hop of those help? I am trying to use JS to update the selected value of multiple select elements, at the same time. For some reason, my JS only updates one select, not all of them on the page. Unfortunately, I am not able to change the id attribute of the select, and the various select elements need to have the same id.
code :
$('#strings option[value=Test]').attr('selected', true);
Updating multiple field with javascript

Updating multiple field with javascript


By : Kyle
Date : March 29 2020, 07:55 AM
With these it helps I would need the body of your proces() function to say for sure, but I think you reference your input field by id, all 5 input fields have the same id. Only first gets updated and that's the problem. Either give different ids (by adding count) or reference by class. That would work, however having same id for multiple fields is not a good idea.
Post the body of the function and I can give more detailed help.
code :
var quan = document.getElementById("quan").value; 
var hiddenfields = document.getElementsByClassName('hidd');
for (var i = 0; i < hiddenfields.length; ++i) {
    var item = hiddenfields[i];  
    item.value = quan;
}
var quan = $("#quan").val();
$( ".hidd" ).val(quan);
$i = 1; 
while($red = mysqli_fetch_assoc($rez)){
                // ...
                echo "<div class=\"col-xs-12  col-sm-12\">
                // ...
                      <input class=\"hidd\" type=\"hidden\" name=\"txtHidd[". $red["id"] ."][kolicina]\" id=\"txtHidd".$i."\" value=\"\"/>
                      <div class=\"col-sm-2 col-xs-4\">
                        <div class=\"form-group\">
                            <input id=\"quan".$i."\" class=\"form-control\" type=\"number\" value=\"0\" min=\"0\" max=\"10\" onChange=\"proces('quan".$i."', 'txtHidd".$i."');\"/>
                        </div>
                      </div>
                // ...
                    </div>";
                $i++;
function proces(quanID, hiddenID) {
    var quan = document.getElementById(quanID).value;         
    document.getElementById(hiddenID).value = quan;
}
             ...

            <input class="hidd" type="hidden" name="xxxxx" id="txtHidd1" value=""/>
                  <div class="col-sm-2 col-xs-4">
                    <div class="form-group">
                        <input id="quan1" class="form-control" type="number" value="0" min="0" max="10" onChange="proces('quan1', 'txtHidd1');"/>
                    </div>
                  </div>


            ...

             ...

            <input class="hidd" type="hidden" name="xxxxxx" id="txtHidd2" value=""/>
                  <div class="col-sm-2 col-xs-4">
                    <div class="form-group">
                        <input id="quan2" class="form-control" type="number" value="0" min="0" max="10" onChange="proces('quan2', 'txtHidd2');"/>
                    </div>
                  </div>


            ...
How to use javascript Promises for updating multiple docs in mongodb?

How to use javascript Promises for updating multiple docs in mongodb?


By : Mozaik3
Date : March 29 2020, 07:55 AM
like below fixes the issue Hi I am writing a script that updates a mongodb database. My script does the following.
code :
File.find({}).exec()
    .then((allElements) => {
        var promises = [];
        for (var i = 0; i < fileJsonArray.length; i++) {
            if (fileJsonArray[i] in allElements) {
                var query = {name : fileJsonArray[i].name, tags: fileJsonArray[i].tags}
                    , update = {size : fileJsonArray[i].size, bmarkedasdeleted: true}
                    , options = {multi: false};
                promises.push(File.update(query, update, options).exec());
                allElements.splice(allElements.indexOf(fileJsonArray[i]), 1);
            } else {
                promises.push(fileJsonArray[i].save());
            }
        }

        for (var i = 0; i < allElements.length; i++) {
            var query = {name : allElements[i].name, tags: allElements[i].tags}
                , update = {bmarkedasdeleted: false}
                , options = {multi: false};
            promises.push(File.update(query, update, options).exec());
        }

        return Promise.all(promises);
    }).then(() => {
        mongoose.disconnect();
        console.log('Disconnect Mongoose.');
    }).catch((err) => {
        console.log(err);
    });
JavaScript-updating multiple slider innerHTML

JavaScript-updating multiple slider innerHTML


By : Moshe Moses Potravny
Date : March 29 2020, 07:55 AM
hop of those help? Alright here is the final answer. But you should really learn to debug your own code. Otherwise you will never be able to finish anything you're building if all your problems end up here.
#1 First of all you need to change the onChange="sliderChange(this.value)" to onChange="sliderChange(this)" and the reason for that is when you are passing the input into SliderChange(), then all you get is a value, rather than the entire input you're touching or using. And it's not smart to pass in a singular value when in reality you may need much more than that. And what do you need more than a value? you need to figure out what input has actually been changed and not only the value of the changed input. And the reason you need to know first what input has been changed is so that you can modify it again and make calls back to it. Because the value from your input doesn't tell you anything about what input has actually been changed so you can change it back again.
code :
for (i = 0; i < index.length; i++){
   if(e == index[i]){
      sliders[i].innerHTML = e.value;
   }
}
function sliderChange(e){
   var index = document.getElementsByTagName('input');
   var sliders = document.getElementsByClassName('sliderStatus');

   for (i = 0; i < index.length; i++){
      if(e == index[i]){
         sliders[i].innerHTML = e.value;
      }
   }
}
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