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How to initialize the dynamic array of chars with a string literal in C++?


How to initialize the dynamic array of chars with a string literal in C++?

By : user2953598
Date : November 21 2020, 01:01 AM
may help you . I want to do the following: , Here's a solution based on std::array:
code :
std::array<char, sizeof("/tmp/file-XXXXXX")> arr{ "/tmp/file-XXXXXX" };
#define DECLARE_LITERAL_ARRAY(name, str) std::array<char, sizeof(str)> name{ str }
DECLARE_LITERAL_ARRAY(arr, "/tmp/file-XXXXXX");


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in c++ is this a good practice to initialize char array with string literal?

in c++ is this a good practice to initialize char array with string literal?


By : user3629686
Date : March 29 2020, 07:55 AM
Any of those help in c++ is this a good practice to initialize char array with string? such as: , This statement
code :
char* abc = (char *) ("abcabc");
const char *abc = "abcabc";
char *abc = "abcabc";
char abc[] = "abcabc";
const char *abc = "abcabc";
std::string abc_str = "abcabc";
const char* abc= abc_str .c_str();
The array expression is not converted into a pointer When a string literal is used to initialize an array of characters

The array expression is not converted into a pointer When a string literal is used to initialize an array of characters


By : Waldo
Date : March 29 2020, 07:55 AM
I wish this helpful for you From C in a Nutshell:
code :
char *ptr = "Hello OP!!";
char arr[] = "Hello OP!! How are you my friend?";
How to initialize an unsigned char array from a string literal?

How to initialize an unsigned char array from a string literal?


By : Us Gift Giant
Date : March 29 2020, 07:55 AM
Hope this helps A simple bytes() should be sufficient in this case. You could also consider bytes { 0,0,0,0.... }.
Also, use std::array, not T[]. Only fools use T[] when they could use std::array.
If C can return only one value(int , char etc.) then how does it returns character string literal(array of chars)?

If C can return only one value(int , char etc.) then how does it returns character string literal(array of chars)?


By : Bhikhu Vaja
Date : March 29 2020, 07:55 AM
it helps some times The statement return "hello World"; returns a char *: a pointer to the first character of the string literal "hello World". This string literal is stored as a null terminated array of 12 char. It is usually stored in memory along with other const data of the program.
Attempting to modify this array invokes undefined behavior. It should be considered const and handled via const char *. It would be safer to define this function as
Which is better way to initialize array of characters using string literal?

Which is better way to initialize array of characters using string literal?


By : Kartikeya
Date : March 29 2020, 07:55 AM
I hope this helps . Unless under special circumstances, always prefer the second way, that is, by not typing the array's size explicitly. This avoids the bug you seemingly unnoticedly created in your example.
To understand this, you should first understand what exactly is a string. The null character is denoted by '\0'. A string is a series of zero or more non-null chars, terminated by a single null character. This last bit is very important. Look at the following code:
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