RoR/Squeel - How do I use Squeel::Nodes::Join/Predicates?

RoR/Squeel - How do I use Squeel::Nodes::Join/Predicates?

By : drm4652
Date : November 21 2020, 01:01 AM
will help you I might as well answer this since I was able to figure out quite a bit through trial and error and by using ruby-doc as a guide. Everything I say here is not a final definition to each of these. It's just what I know that may be able to help someone out in the future in case anyone else is stuck making dynamic queries with Squeel.
code :

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Squeel to execute outer join on Rails

Squeel to execute outer join on Rails

By : VishnuVardhanreddy
Date : March 29 2020, 07:55 AM
Does that help I think you can try something like the below using Squeel. I am not sure about the where part. You will have to give one of the two join conditions.
code :
Building.joins{city}.joins(city_buildings.outer).where{(buidlings.id == city_buildings.building_id) & (cities.id == city_buildings.city_id)}
Building.joins{city}.joins(city_buildings.outer).where{buidlings.id == city_buildings.building_id}
Building.joins{city}.joins(city_buildings.outer).where{cities.id == city_buildings.city_id}
Using NOT with Squeel

Using NOT with Squeel

By : philip
Date : March 29 2020, 07:55 AM
I hope this helps you . Say I have a set of conditions: , You'll want to use the unary minus operator.
code :
Person.where{-((name =~ 'Ernie%') & (salary < 50000) | (name =~ 'Joe%') & (salary > 100000))}.to_sql
=> "SELECT \"people\".* FROM \"people\"  WHERE (NOT (((\"people\".\"name\" LIKE 'Ernie%' AND \"people\".\"salary\" < 50000) OR (\"people\".\"name\" LIKE 'Joe%' AND \"people\".\"salary\" > 100000))))" 
how to join a subquery with conditions in Squeel

how to join a subquery with conditions in Squeel

By : Lauro Madalosso Nune
Date : March 29 2020, 07:55 AM
this one helps. Like I said - preferably using Squeel :)
It turns out that (from the horses mouth so to speak) joins are for associations in Squeel-county ;)
code :
Model.select("something").joins("to your hearts contend")
Using NOT operator with Squeel?

Using NOT operator with Squeel?

By : D. Schlegel
Date : March 29 2020, 07:55 AM
hope this fix your issue It's very important to notice that ActiveRecord stores boolean values as string flags in the database. Therefore, in the case you mentioned, document.deleted equals 'f' which is a truthy value. That's why you can't simply use the NOT operator.
Perhaps what you're looking for is:
code :
Document.where { deleted.eq(false) | deleted.eq(nil) }
ActiveRecords Join with conditions: how to join on the same table with different sets of conditions using squeel sifters

ActiveRecords Join with conditions: how to join on the same table with different sets of conditions using squeel sifters

By : Allinone
Date : March 29 2020, 07:55 AM
wish of those help This is the case where you need to take the intersection of sets of users. In other words, you need to apply the "AND" to the sets of users, not to the where conditions. When you chain where conditions, you are "anding" the conditions, which is why you see the results you're seeing.
You can do this either in Ruby or in SQL, using the basic technique described in Intersection of two relations. For the sake of simplicity, I'll illustrate both here using two sets and leave the extension to more than two sets and to squeel to you.
code :
set1 = User.joins(:user_skills).where('user_skills.skill_id = 10')
set2 = User.joins(:user_skills).where('user_skills.skill_id = 11 and user_skills.value >= 2')
set1 & set2
User.connection.unprepared_statement do
  User.find_by_sql "#{set1.to_sql} INTERSECT #{set2.to_sql}"
query1 INTERSECT query2 INTERSECT query3 ...
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