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How to check if the second list element on a line in a file contains 'x'?


How to check if the second list element on a line in a file contains 'x'?

By : user2953349
Date : November 20 2020, 01:01 AM
I hope this helps you . What I'm trying to do is to create a login system. , You could use dictionaries to store the password of each user:
code :
dictPass = {i.split()[0]:i.split()[1] for i in users}
if username.lower() in d:
if password == d[username.lower()]:
if password == d.get(username.lower()):
whichUser = usernames.index(username.lower())
realPassword = passwords[whichUser]


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Python -- How can I check every line of a file to see if it contains an item from a list and if it does delete that line

Python -- How can I check every line of a file to see if it contains an item from a list and if it does delete that line


By : frex89
Date : March 29 2020, 07:55 AM
This might help you , I presume this is what you want to do:
code :
outfile = file("outfile.txt", "w")
lines_to_check_for = [ line for line in file("list.txt", "r") ]
for line in file("testing.txt", "r"):
    if not line in lines_to_check_for:
        outfile.write(line)
newusers = file("newusers.txt", "w")
existing_users = [ line for line in file("users.txt", "r") ]
for line in file("testing.txt", "r"):
    # grab each comma-separated user, take the portion left of the @, if any
    new_users = [ entry.split["@"](0) for entry in line.split(",") ]
    for user in new_users:
        if not user in existing_users:
            newusers.write(user)
check if any of the items of a list is in a line of a file, if not, then write the line in a new file

check if any of the items of a list is in a line of a file, if not, then write the line in a new file


By : Rayson Jimenez
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have a file that has a lot of lines and I need to create a new file, excluding the lines that contains some words.
code :
infile = file('./infile_test.txt')
outfile = open('./newfile.txt', 'w')

ignore_list = ['ssh', 'snmp', 'etc']

for line in infile:
    if not any(word in line for word in ignore_list):
        outfile.write(line)
Open a file, split each line into a list, then for each word on each line check to see if the word is in list and if not

Open a file, split each line into a list, then for each word on each line check to see if the word is in list and if not


By : JaredWest1994
Date : March 29 2020, 07:55 AM
help you fix your problem What is the best way to perform the following? The sample document (hello.txt) contains the following: , Your error lies in these two lines:
code :
for word in words:
     if word not in words:
for word in words:
     if word not in lst:
import string
result = sorted(set(
    word.strip(string.punctuation)
    for line in open('hello.txt')
    for word in line.split()))
print result
How do I read a file line by line and read a list element by element simultaneous in python

How do I read a file line by line and read a list element by element simultaneous in python


By : Black Trio
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Use zip:
code :
for line, item in zip (open ('myfile.txt'), mylist):
  print (line)
  print (item)
Check if a list contain element of a csv file

Check if a list contain element of a csv file


By : GothicIII
Date : March 29 2020, 07:55 AM
I wish this helpful for you I have a csv file with items like these: some,foo,bar and i have a different list in python with different item like att1,some,bar,try,other . Is possible for every list, create a row in the same csv file and set 1 in correspondence of the 'key' is present and 0 otherwise? So in this case the csv file result would be: , You could create a dictionary with the keys as the column names.
code :
csv = {
  "some" : [],
  "foo" : [],
  "bar" : []
}
for list in lists:
  for key in csv.keys():
    if key in list:
       csv[key].append(1)
    else:
       csv[key].append(0)
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