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readline function returning empty string


readline function returning empty string

By : user2953296
Date : November 20 2020, 01:01 AM
help you fix your problem I am new to Python; little experience in programming C++. I saw this question but it doesn't address my problem. , If you want to modify the lines your way:
code :
def transform_line(line):
    if line != "":
        if line[0].isdigit():
            print("O")
        elif line[0] in {"+", "-"}:
            print("U")
    else:
        print("None")
    return line

with open("./testStage1.txt", 'r') as osrc:
    osrc.seek(291)
    lines = [transform_line(line) for line in osrc]
    #Do whatever you need with your line list
with open("./testStage1.txt", 'r') as osrc:
    osrc.seek(291)
    lines = list(osrc)
    #Do whatever you need with your line list
def line_iterator(file):
    for line in file:
        if not line[0].isdigit() and not line in ["+", "-"]:
            yield line
        else:
            break

with open("./testStage1.txt", 'r') as osrc:
    osrc.seek(291)
    lines = list(line_iterator(osrc))
    #To skip lines from the list containing 'blah'
    lines = [x for x in lines if 'blah' not in line]
    #Do whatever you need with your line list


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Why my function is returning empty string in python?

Why my function is returning empty string in python?


By : user1989727
Date : March 29 2020, 07:55 AM
hop of those help? What I am doing is, removing all parts of speech except nouns from a text. , You need to close the file first:
code :
for line in fin:
    for word in a:
       line = line.replace(word, "")
           fout.write(line)
fout.close()
def extract_nouns(i_location, o_location):
    import nltk

    with open(i_location, "r") as myfile:
      data = myfile.read().replace('\n', '')

    tokens = nltk.word_tokenize(data)
    tagged = nltk.pos_tag(tokens)
    length = len(tagged)
    a = []

    for i in range(0,length):
       print(i)
       log = (tagged[i][1][0] == 'N')
       if not log:
           a.append(tagged[i][0])
    with open(i_location, 'r') as fin, open(o_location, "w+")  as fout:
        for line in fin:
            for word in a:
               line = line.replace(word, "")
            fout.write(line)
            fout.seek(0) # go back to start of file
            data_out = fout.read().replace('\n' , '')
        return data_out
Python seek() followed by a readline() gives empty string

Python seek() followed by a readline() gives empty string


By : avidelecteur
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I don't get what is string.split? Do you mean str.split? From what you are trying to do - it looks like - you want to split all lines that have $ in them into parts and ignore other lines. And in your particular case those lines seem to be at the beginning of file. A simpler approach would be
code :
for line in fp:
    if line.find('$') >= 0:
        line.split('$')  # or str.split(line, '$')
' 2015-06-09 08:18:23 [coryj@Corys-MacBook-Pro ~]$ ping 10.2.2.1'
Readline function returning the first line

Readline function returning the first line


By : Patrick Lolot de Alb
Date : March 29 2020, 07:55 AM
this one helps. inp.readline(n) returns either the entire line, or the number of bytes in the current line, whichever is lesser. If you want to read by bytes, I suggest you use inp.read(n). Alternatively, use a loop over inp
code :
def swapfunction ():
    inp = open('cube.xyz', 'r+')
    for line in inp:
        print line,

swapfunction()
4  

'Cu' 0.0 0.0 0.0 0.5  
'Ag' 0.0 0.0 1.0 0.5  
'Ag' 0.0 0.0 2.0 0.5  
'Cu' 0.0 0.0 3.0 0.5
Recursive function returning empty string

Recursive function returning empty string


By : user3097134
Date : March 29 2020, 07:55 AM
This might help you A proper recursive function doesn't need a specific exit condition. You just stop calling the function recursively, and it exits.
However, if you want to explicitly exit, you can use Exit Function.
code :
Public Function RemoveMultipleSpaces(s As String) As String
    If InStr(1, s, "  ", vbTextCompare) > 0 Then
        Dim newS As String
        newS = Replace(s, "  ", " ")
        RemoveMultipleSpaces = RemoveMultipleSpaces(newS)
    Else
        RemoveMultipleSpaces = s
    End If
End Function
Why is the Function Returning an Empty String

Why is the Function Returning an Empty String


By : Vakel
Date : March 29 2020, 07:55 AM
I wish did fix the issue. You're using reference std::basic_string::operator[](size_t pos) to get the first element in a string and then its address using the & operator. However, as per the function's specification, if pos == size then it's undefined behaviour. C++11 standard, draft N3337, [string.access], basic_string element access (emphasis mine):
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