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Function return a function that returns a function


Function return a function that returns a function

By : Makarand Kate
Date : November 19 2020, 03:59 PM
With these it helps Thomas's answer should work, but if you want a more typesafe alternative:
code :
struct F {
    let f: (Character) -> F
}

func f(ch: Character) -> F {
    println("I've been called with an \(ch)!")
    return F(f: f)
}

let g = f("a")
let h = g.f("b")
h.f("c")


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Can I write a JS function that: returns as a normal function would or wait and return AJAX results?

Can I write a JS function that: returns as a normal function would or wait and return AJAX results?


By : Abdallah Daragmeh
Date : March 29 2020, 07:55 AM
I hope this helps you . Currently, I have a function getData that makes an AJAX call for some data, stores it in localStorage, and then calls the callback. If the data is already in localStorage, then getData will just call the callback. , Due to the asynchronous nature of AJAX, it is not possible to write:
code :
function getData(){
  var result;
  $.ajax({
    url: 'script.php',
    type: 'POST',
    dataType: 'html',
    cache: false,
    succes: function(data){
      result = data;
    }
  });
  return result;
}

var data = getData();
console.log(data);  //undefined
function getData(){
  var result;
  $.ajax({
    url: 'submit.php',
    type: 'POST',
    dataType: 'html',
    async: false,
    success: function(data){
      result = data;
    }
  });
  return result;
}

var data = getData();
console.log(data); // Server's response
getData(function(data){
    // do something with data
});
function getData(){
  return $.ajax({
    url: 'submit.php',
    type: 'POST',
    dataType: 'html'
  });
}

var data = getData()
.success(function(data){
  console.log(data);
})
.fail(function(){
  console.log("Error!");
});
function getData(key){
  var data = localStorage.getItem(key);

  if (data){
    return $.Deferred().resolve(data);
  } else {
    return $.ajax({
      url: 'submit.php',
      type: 'POST',
      dataType: 'html',
      cache: false
    });
  }
}

var data = getData("key").done(function(data){
  localStorage.setItem("key", data);
  console.log(data)
});
function getData(){
  var KEY = 'key',
      data = localStorage.getItem(KEY),
      retVal;

  if (data){
    retVal = data;
  } else {
    $.ajax({
      url: 'submit.php',
      type: 'POST',
      dataType: 'html',
      async: false,
      success: function(data){
        retVal = data;
        localStorage.setItem(KEY, data);
      }
    });
  }

  return retVal;
}

var data = getData();
console.log(data);
UML Class Diagram: What goes in the return type for the function if the function returns a function call?

UML Class Diagram: What goes in the return type for the function if the function returns a function call?


By : Kim Na Na
Date : March 29 2020, 07:55 AM
Any of those help Actually your question is not correct. Your function func does not return a function, but the result of a function. To my knowledge there is no common type representing a function. The return of an operation is a Type
code :
[<visibility>] <name> ‘(‘ [<parameter-list>] ‘)’ [‘:’ [<return-type>] [‘[‘ <multiplicity-range> ‘]’] [‘{‘ <oper-property> [‘,’ <oper-property>]* ‘}’]] 
Recursive function returns 0 when its done. Why doesn't 'return 0' override the previous return value of the function?

Recursive function returns 0 when its done. Why doesn't 'return 0' override the previous return value of the function?


By : chaw
Date : March 29 2020, 07:55 AM
With these it helps Because the first call of the function is the last one that returns. Assume you have the list [1,2,3]. You code will end up with
code :
return 1 + sum([2, 3])
return 1 + (return 2 + sum([3]))
return 1 + (return 2 + (return 3 + sum([])))
return 1 + (return 2 + (return 3 + 0))
return 1 + (return 2 + 3)
return 1 + 5
return 6
How to check a `missing return type on function` if my function returns another function?

How to check a `missing return type on function` if my function returns another function?


By : nandu
Date : March 29 2020, 07:55 AM
will be helpful for those in need I have a function that returns another function. I am using a default config for a CRA with typescript and eslint @typescript-eslint/explicit-function-return-type this rule of eslint tells me I need to describe what is going to be a result of the execution of the first function. It looks like middleware. I don't know how to describe a type for that , This is one way to type it:
code :
type Fn = <A>(a: A) => (<B extends (a: A) => any>(b: B) => ReturnType<B>);
let fn: Fn = a => b => b(a);

const str = fn(1)(a => String(a)); // str is string
const num = fn('a')(a => Number(a)) // num is number
const num2 = fn(2)(a => a + 2) // num2 is number
JavaScript: Create Function that Returns Function in which Returned Function Invokes Passed Function

JavaScript: Create Function that Returns Function in which Returned Function Invokes Passed Function


By : user2977754
Date : March 29 2020, 07:55 AM
hope this fix your issue I am trying to create a function "thrice" that returns another function. , Notice that
code :
thrice(() => {
  return 8;
});
eight = ()=> thrice(() => {
  return 8;
});
// or

eight =function(){ thrice(() => {
  return 8;
});};
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