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intern() string of query result


intern() string of query result

By : Mohd Rashid
Date : November 19 2020, 03:59 PM
To fix the issue you can do A much better solution would be to use the number (int) for the first column. This should work:
code :
 BigDecimal result = resultAsBigDecimal( (Number)tempResult[0] );

 public static BigDecimal resultAsBigDecimal( Number value ) {
     int i = value.intValue();
     if( 0 == i ) return BigDecimal.ZERO;
     if( 1 == i ) return BigDecimal.ONE;
     throw new RuntimException( "Unexpected value: " + value );
 }


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Can we access or query the Java String intern (constant) pool?

Can we access or query the Java String intern (constant) pool?


By : CosyOcch
Date : March 29 2020, 07:55 AM
Hope this helps You cannot directly access the String intern pool.
As per Javadocs String intern pool is:
How do I get intern.js 2.1 to work with the new functionalSuites command line argument to intern-runner?

How do I get intern.js 2.1 to work with the new functionalSuites command line argument to intern-runner?


By : Saurabh
Date : March 29 2020, 07:55 AM
I wish did fix the issue. This was due to a bug in how Intern 2.1.0 handled the functionalSuites property. Intern has always assumed functionalSuites is an array. Specifying only a single instance of functionalSuites on the command line resulted in a string value (rather than an array) for functionalSuites in Intern, which would break the test runner.
The problem is fixed in Intern 2.1.1.
Java String intern function result problem

Java String intern function result problem


By : user3498113
Date : March 29 2020, 07:55 AM
it fixes the issue Let's look at what intern actually does (emphasis mine):
code :
str2.intern();
String s4 = new String("1");
Getting multi result from sql result and put into foreach query , got Array to string conversion error

Getting multi result from sql result and put into foreach query , got Array to string conversion error


By : dony17_
Date : March 29 2020, 07:55 AM
may help you . You are trying to access the values in an associative array using numeric indexes. Use the column names instead. mysqli_fetch_assoc() returns an associative array.
Instead of this,
code :
$get_row[1]
$get_row['column_name']
...LIKE ArrayORDER BY...
...LIKE Array ORDER BY...
'SELECT * FROM pc WHERE pcSN LIKE '.$SN.'ORDER BY EvenID DESC LIMIT 1'
'SELECT * FROM pc WHERE pcSN LIKE '.$SN.' ORDER BY EvenID DESC LIMIT 1'
String#intern the confuse about the result of the intern

String#intern the confuse about the result of the intern


By : murali j
Date : March 29 2020, 07:55 AM
wish help you to fix your issue A String literal is always automatically interned the first time it appears. The String literals you have in your code are "11" and "2".
On the other hand, the String created as a result of String concatenation is not automatically interned.
code :
String a = new String("11"); // interns the String literal "11", and creates a
                             // different String instance referenced by a
a.intern(); // doesn't add a to the String pool, since "11" is already in 
            // the String pool
String b = "11"; // "11" returns the canonical instance already in the pool,
                 // which is != a
String c = new String("2") + new String("2"); // interns the String "2", creates 2 
                                              // more Strings having the same value,
                                              // and creates an additional String
                                              // whose value is "22", which is not
                                              // interned yet
c.intern(); // c is added to the String pool as the canonical instance whose value
            // is "22"
String d = "22"; // "22" returns the canonical instance already in the pool,
                 // which is == c
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