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parse json structure from excel sheet into java


parse json structure from excel sheet into java

By : user2952909
Date : November 19 2020, 03:59 PM
Does that help You can parse JSON into Java object in one line like this,
http://wiki.fasterxml.com/JacksonInFiveMinutes
code :
Map<String,Object> c_data = mapper.readValue(c1Val, Map.class);
String minimum = c_data.get("minimum");
String maximum= c_data.get("maximum");


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How to parse jquery.sheet's JSON in Java?

How to parse jquery.sheet's JSON in Java?


By : user
Date : March 29 2020, 07:55 AM
To fix the issue you can do Strictly speaking the sample you are referring to is not a valid JSON, e.g. it lacks "" around field ids as metadata [according to JSON defined in www.json.org][http://json.org/]
For this reason I would recommend that before you pass it to your Java (e.g. servlet) you should stringify this object, e.g. as shown in this answer. This way you are sure that this is a valid JSON. Later use jQuery to send it to servlet. There in your Java code you use the below code to get your json String turned into JSONArray on which you will operate further.
code :
String json = request.getParameter(param);
JSONArray jsonArray = new JSONArray(json);
for (int i = 0; i < jsonArray.length(); i++) {
   JSONObject jsonObject = jsonArray.getJSONObject(i);
   //work with the jsonObject
}
How export json data to excel sheet in java

How export json data to excel sheet in java


By : Twenyone
Date : March 29 2020, 07:55 AM
hope this fix your issue Questions on exporting JSON to CSV have been previously asked here and a response was provided here: Converting JSON to XLS/CSV in Java
However since you asked for a tutorial this page shows an example with a different approach.
Java FastXML JSON library: How to parse a nested JSON structure

Java FastXML JSON library: How to parse a nested JSON structure


By : Merigi
Date : March 29 2020, 07:55 AM
I hope this helps . Two things to consider:
If you want to keep streaming, calling jp.readValueAsTree() is not a good idea as that will allocate memory to create the tree with all data under the current node (in your code, everything under "matches"), unless you know for sure this is a small tree. To get to a value in an array, there is no need to create an array first. The streaming API will let you walk to the value in the array you need.
code :
import java.io.*;
import java.util.*;

import com.fasterxml.jackson.core.*;
import com.fasterxml.jackson.databind.*;

/**
 * http://stackoverflow.com/q/30288878/3080094
 * Using jackson-databind-2.5.3 which uses
 * jackson-annotations-2.5.0 and
 * jackson-core-2.5.3
 * @author vanOekel
 */
public class JsonTest {

    public static void main(String[] args) {

        try {
            new JsonTest().getNames();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    ObjectMapper jsonMapper = new ObjectMapper();
    JsonFactory jsonFactory = new JsonFactory();

    void getNames() throws Exception {

        final String resourceName = "some.json";
        JsonNode jn;
        try (InputStream in = 
                Thread.currentThread().getContextClassLoader().getResourceAsStream(resourceName)
                ) {
            if (in == null) {
                throw new FileNotFoundException("File not found: " + resourceName);
            }
            jn = jsonMapper.readTree(in);
        } 
        findByPath(jn);

        try (InputStream in = 
                Thread.currentThread().getContextClassLoader().getResourceAsStream(resourceName)
                ) {
            if (in == null) {
                throw new FileNotFoundException("File not found: " + resourceName);
            }
            JsonParser jsonParser = jsonFactory.createParser(in);
            findInStream(jsonParser);
        } 
    }

    final String[] path = new String[] {"myReport", "docReports", "part1/.", "myAnalysis", "matches", "name"};

    void findByPath(JsonNode jn) {

        JsonNode matchesNamesNode = jn;
        for (int i = 0; i < path.length - 1; i++) {
            matchesNamesNode = matchesNamesNode.path(path[i]);
        }
        if (matchesNamesNode.isMissingNode()) {
            throw new RuntimeException("No node with names found.");
        }
        System.out.println("Tree names: " + matchesNamesNode.findValuesAsText(path[path.length - 1]));
    }

    void findInStream(JsonParser jp) throws Exception {

        int pathIndex = 0;
        List<String> names = new ArrayList<String>();
        boolean breakOnClose = false;

        while (jp.nextToken() != null) {
            final String fieldName = jp.getCurrentName();
            if (fieldName == null) {
                continue;
            }
            if (breakOnClose && fieldName.equals(path[path.length - 2])) {
                System.out.println("Stopping search at end of node " + fieldName);
                break;
            }
            if (jp.getCurrentToken() != JsonToken.FIELD_NAME) {
                continue;
            }
            // System.out.println("Field " + fieldName);
            if (pathIndex >= path.length - 1) {
                if (fieldName.equals(path[path.length - 1])) {
                    // move from field name to field value.
                    jp.nextToken(); 
                    String name = jp.getValueAsString();
                    if (name == null) {
                        throw new RuntimeException("No value exists for field " + fieldName);
                    }
                    names.add(name);
                    System.out.println("Found " + fieldName + " value: " + name);
                }
            } else if (fieldName.equals(path[pathIndex])) {
                System.out.println("Found node " + path[pathIndex]);
                pathIndex++;
                if (pathIndex >= path.length - 1) {
                    System.out.println("Looking for names ...");
                    breakOnClose = true;
                    // prevent breaking on "matches" value json-token.
                    jp.nextFieldName(); 
                }
            }
        }
        System.out.println("Streaming names: " + names);
    }

}
How to parse this Json structure in Java

How to parse this Json structure in Java


By : user3880600
Date : March 29 2020, 07:55 AM
hope this fix your issue You should call arr.getString(i) directly.
Generate Excel sheet report fron json array in java

Generate Excel sheet report fron json array in java


By : Satendra
Date : March 29 2020, 07:55 AM
will help you You can use Apache POI for this and use classes like XSSFWorkbook, XSSFSheet, Row, Cell.
code :
JSONObject jsonObj = new JSONObject(jsonString.toString()); //convert to json object
JSONArray objSearchOrdersDto = jsonObj.getJSONArray("objSearchOrdersDto"); // convert to json array


XSSFWorkbook workbook = new XSSFWorkbook();
        XSSFSheet sheet = workbook.createSheet("Report");

        int rowCount = 0;
        for (int i = 0; i < objSearchOrdersDto.length(); ++i)
        {
            JSONObject rec = objSearchOrdersDto.getJSONObject(i);
            int OrderNumber = rec.getInt("OrderNumber");
            String strStatusType = rec.getString("strStatusType");
            int OrgUnitId = rec.getInt("OrgUnitId");

            Row row = sheet.createRow(++rowCount);
            Cell cell1 = row.createCell(1);
            cell1.setCellValue(OrderNumber);
            Cell cell2 = row.createCell(2);
            cell2.setCellValue(strStatusType);
            Cell cell3 = row.createCell(3);
            cell3.setCellValue(OrgUnitId);
            System.out.println(OrderNumber+"\t"+strStatusType+"\t"+OrgUnitId); //want to excel file for this three field
        }


        try (FileOutputStream outputStream = new FileOutputStream("Report.xlsx")) {
            workbook.write(outputStream);
        }
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