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How to schedule automatic increment for a column on a particular date


How to schedule automatic increment for a column on a particular date

By : LeChuck
Date : November 19 2020, 03:59 PM
I think the issue was by ths following , I have a table with the details of employees, which also enlists how many leaves of each type has an employee availed. The table is scripted as : , You have some options:
code :


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p:schedule Incorrectly displays event in schedule which have identical start and end date-time

p:schedule Incorrectly displays event in schedule which have identical start and end date-time


By : Mithlesh Jha
Date : March 29 2020, 07:55 AM
Does that help
I assume you did not do some debugging and little experimentation to. First of all it only happens with events of 0 duration, not 'less than one hour' (corrected your title) In the response you'll see that, when you create a 0 (zero) duration event, the start-date-time and end-date-time are reported correctly.
code :
<?xml version='1.0' encoding='UTF-8'?>
<partial-response id="j_id1">
  <changes>
    <update id="j_idt88:schedule"><![CDATA[{"events" : [
      {"id": "3fbce3ee-7747-4cef-8362-c8d08d004c6e","title": "Champions League Match","start": "2016-02-17T21:00:00+0200","end": "2016-02-18T00:00:00+0200","allDay":false,"editable":true},
      {"id": "df70f7f0-6806-49a8-8991-9b109c397757","title": "Birthday Party","start": "2016-02-18T14:00:00+0200","end": "2016-02-18T19:00:00+0200","allDay":false,"editable":true},
      {"id": "7415213a-d721-4ffd-a60a-d82e88528c78","title": "Breakfast at Tiffanys","start": "2016-02-19T10:00:00+0200","end": "2016-02-19T12:00:00+0200","allDay":false,"editable":true},
      {"id": "81c0149b-0850-4b90-a345-4e89a764a2a5","title": "Plant the new garden stuff","start": "2016-02-20T16:00:00+0200","end": "2016-02-22T16:00:00+0200","allDay":false,"editable":true},
      {"id": "8087111d-c559-4add-a498-2f3f58a02f0d","title": "MyNewEvent","start": "2016-02-16T12:30:00+0200","end": "2016-02-16T12:30:00+0200","allDay":false,"editable":true}]}]]>
    </update>
    <update id="j_id1:javax.faces.ViewState:0">
      <![CDATA[5869453577302409685:-7766841559488939365]]>
    </update></changes>
</partial-response>
defaultTimedEventDuration:"02:00:00"
function scheduleExt() {
   //this = schedule widget instance
   //this.cfg = options
   this.cfg.defaultTimedEventDuration:"02:00:00"
   };
}
t sql increment date column value based on previous row date value

t sql increment date column value based on previous row date value


By : John
Date : March 29 2020, 07:55 AM
This might help you I have columns of data in table #Temp1 as follows: (there is an existing clustered Index on the table of Unit asc, dateTime asc) , You can use window functions and an updatable CTE:
code :
with toupdate as (
      select t.*,
             row_number() over (partition by unit order by datetime) as seqnum,
             min(datetime) over (partition by unit) as min_datetime
      from #temp1 t
     )
update toupdate
    set datetime = dateadd(minute, 2 * seqnum - 2, min_datetime)
    where seqnum > 1;
Write a query to display schedule id and date in the format of ‘YYYY-MM-DD’ and name the column as FormattedDate

Write a query to display schedule id and date in the format of ‘YYYY-MM-DD’ and name the column as FormattedDate


By : Taha Boz
Date : March 29 2020, 07:55 AM
To fix this issue travel_date is already a DATE data type; there is no need to use TO_DATE( date_string, format_model ) on it as the function expects a string as the first argument and you are passing a DATE so oracle has to apply an implicit conversion (using the NLS_DATE_FORMAT session parameter as the format model) and your statement is effectively:
code :
select schedule_id,
       to_char(
         to_date(
           TO_CHAR(
             travel_date,
             (SELECT VALUE FROM NLS_SESSION_PARAMETERS WHERE PARAMETER = 'NLS_DATE_FORMAT')
           ),
           'DD-MON-YY'
         ),
         'YYYY-MM-DD'
       ) as FormattedDate
from   schedule
order by schedule_id;
select schedule_id,
       to_char( travel_date, 'YYYY-MM-DD' ) as FormattedDate
from   schedule
order by schedule_id;
select schedule_id,
       to_char( travel_date, 'YYYY-MM-DD' ) as "FormattedDate"
from   schedule
order by schedule_id;
How to increment date using previous value from same column and skip weekend date?

How to increment date using previous value from same column and skip weekend date?


By : user3245392
Date : March 29 2020, 07:55 AM
I wish did fix the issue. This seems quite tricky. I think my best advice is to reconstruct the data. A relatively simple method uses a recursive CTE:
code :
with cte as (
      select min(originaldate) as dte, count(*) as cnt, min(originaldate) as originaldate
      from t
      union all
      select (case when datename(weekday, v.nextdate) = 'Saturday' then dateadd(day, 2, nextdate)
                   when datename(weekday, v.nextdate) = 'Sunday' then dateadd(day, 1, nextdate)
                   else v.nextdate
              end),
             cnt - 1, dateadd(day, 1, originaldate)

      from cte cross apply
           (values (dateadd(day, 1, dte))) v(nextdate)
      where cnt > 0
     )
select originaldate, dte
from cte
order by originaldate;
Increment date column by VBA excel

Increment date column by VBA excel


By : user3492216
Date : March 29 2020, 07:55 AM
This might help you if i have a column in excel in following format: "dd/mm/yyyy hh:mm:ss" and i want to increase the hour value by 1. I add 1/24 to that cell and is done. , You could try:
code :
Option Explicit

Sub test()

    Dim arr As Variant
    Dim Initial_DateTime As Date
    Dim i As Long

    With ThisWorkbook.Worksheets("Sheet1")

        arr = .Range("A2:A10000")

        For i = LBound(arr) To UBound(arr)

            Initial_DateTime = arr(i, 1)

            arr(i, 1) = DateAdd("h", 1, Initial_DateTime)

        Next i

        .Range("A2:A1000").Value = arr

    End With

End Sub
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