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Regex for checking names with _0, _1 at the end?


Regex for checking names with _0, _1 at the end?

By : Michael Buluma
Date : November 19 2020, 03:59 PM
help you fix your problem
I want to find out how to ensure that the group (_digit) as a whole is repeated 0 or more times ?
code :
(?:_\d)*$
(?:_\d+)*$
(?:_[01])*$
> /(?:_\d)*$/.test('abc_0')
true
> /(?:_\d)*$/.test('dog')
true


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php class or regex to check regex pattern itself (at least checking the delimiters/syntax..)

php class or regex to check regex pattern itself (at least checking the delimiters/syntax..)


By : user3309190
Date : March 29 2020, 07:55 AM
help you fix your problem The easiest way would be to just try using preg_match() with the regex on an empty string; if it returns False, an error has occurred, meaning that the pattern is invalid.
What's a good reason to use RegEx constructor properties' short names in lieu of the verbose names?

What's a good reason to use RegEx constructor properties' short names in lieu of the verbose names?


By : Amir Ali
Date : March 29 2020, 07:55 AM
Does that help Looks like RegExp.["$`"] and RegExp.["$'"] are aleady "dead", and RegExp.$+ and RegExp.$& behave unexpectedly.
Current (April 30, 2015) output:
code :
var text = "this has been a short summer"; 
var pattern = /(.)hort/g; 



 if (pattern.exec(text) != null) {

   document.getElementById("res").innerHTML += "<b>RegExp.input</b>: " + RegExp.input + "<br />";               // this has been a short summer 
   document.getElementById("res").innerHTML += "<b>RegExp.$_</b>: " + RegExp.$_ + "<br />";                  // this has been a short summer 
   
   document.getElementById("res").innerHTML += "<b>RegExp.leftContext</b>: " + RegExp.leftContext + "<br />";       // this has been a 
   //document.getElementById("res").innerHTML += RegExp.["$`"] + "<br />";            // this has been a, now, does not let compile

   document.getElementById("res").innerHTML += "<b>RegExp.rightContext</b>: " + RegExp.rightContext + "<br />";    // summer 
   //document.getElementById("res").innerHTML += RegExp.["$'"] + "<br />";           // summer, now, does not let compile

   document.getElementById("res").innerHTML += "<b>RegExp.lastMatch</b>: " + RegExp.lastMatch + "<br />";           // short 
   document.getElementById("res").innerHTML += "<b>RegExp.$&</b>: " + RegExp.$& + "<br />";                  // was "short", now, evaluates the expression on the right to 0

   document.getElementById("res").innerHTML += "<br /><b>RegExp.lastParen</b>: " + RegExp.lastParen + "<br />";          // s 
   document.getElementById("res").innerHTML += "<b>RegExp.$+</b>: " + RegExp.$+ + "<br />";                 // was "s", now, outputs "NaN"

  }
<div id="res" />
Regex for extracting full names from string of names and emails

Regex for extracting full names from string of names and emails


By : stoic94
Date : March 29 2020, 07:55 AM
hop of those help? The Trick: Splitting vs. Matching
This is one of those questions that look hard if you try to match the text. The trick is to match the emails, and the adjoining spaces, and to split on that. You can split using this regex:
code :
(?i)\s*\b[A-Z0-9._%+-]+@[A-Z0-9.-_]+\.[A-Z]{2,6}\b\s*
$result = preg_split('/(?i)\s*\b[A-Z0-9._%+-]+@[A-Z0-9.-_]+\.[A-Z]{2,6}\b\s*/im', $str, 0);
Regex for Names where the middle and last names are optional. (Python)

Regex for Names where the middle and last names are optional. (Python)


By : Scott
Date : March 29 2020, 07:55 AM
wish of those help I am trying to match space seperated names that do not contain any special character. The first name is compulsory and the middle and last names are optional. Also, the names could have all capital letters, but not all small, and the first character of each of the names(first, middle, last) is a capital letter. , What you want is
code :
^[A-Z]\w+(?:\s[A-Z]\w+?)?\s(?:[A-Z]\w+?)?$
\s[A-Z]\w+(?:\s[A-Z]\w+?)?\s(?:[A-Z]\w+?)?[\s\.\,\;\:]
Find names in string using regex without including first names if second name is present

Find names in string using regex without including first names if second name is present


By : Genus88
Date : March 29 2020, 07:55 AM
this will help It seems you're looking for negative lookaround assertions.
For example, jon(?! snow) matches "jon", but only if " snow" does not follow.
code :
$names = 'jon(?! snow)|jon snow|lana(?! smith)|(?<!lana )smith|lana smith|megan';
$names = 'jon snow|jon|lana smith|lana|smith|megan';
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