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variable substitution (what do you call/name this method)?


variable substitution (what do you call/name this method)?

By : Alessandro Lasmar Mo
Date : November 19 2020, 03:59 PM
I wish this helpful for you Say in bash I have: , You can use an indirect reference for that:
code :
$ c=3
$ b3=4
$ d=b$c
$ echo "${!d}"
4


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Python subprocess.call with variable substitution

Python subprocess.call with variable substitution


By : shanawaz Ali
Date : March 29 2020, 07:55 AM
help you fix your problem Use os.path.join:
code :
subprocess.call(["/bin/cp", "-a",
    os.path.join(MOST_POPULAR_REPORTS_LOCATION, MOST_POPULAR_REPORTS_FILE), 
        TEMP_DATA_FILE_LOCATION])
Between *variable sharing* and *command substitution*, which method is better for returning a value from another bash sc

Between *variable sharing* and *command substitution*, which method is better for returning a value from another bash sc


By : Josephine
Date : March 29 2020, 07:55 AM
Hope that helps Little introduction
Tracking forks (like $()) as they consume lot more ressource than normal (sequential) execution, if you know which variable has to be modified in advance, you'll better to use local definition around your whole script and use function instead of having to make file access between commands:
code :
#!/bin/bash
# There is the `A` script

local VAR

function B() {
    read -a VAR </proc/uptime
}

B
echo $VAR
sleep 1
B
echo $VAR
1610291.39
1610292.39
local V1
B1() {
    read -a V1 </proc/uptime
}
B1 ;echo $V1 ;for i in {0..10000} ;do B1 ;done ;echo $V1
1610843.78
1610844.38
printf "%d 1/100th of sec\n" $((161084438-161084378))
60 1/100th of sec
B2() {
    local var
    read -a var </proc/uptime
    echo $var
}
V2=$(B2);echo $V2;for i in {0..10000};do V2=$(B2);done;echo $V2
1611121.33
1611168.01
printf "%d 1/100th of sec\n" $((161116801-161112133))
4668 1/100th of sec
echo >/dev/shm/B3 'read -a V3 </proc/uptime'
. /dev/shm/B3 ;echo $V3 ; for i in {0..10000};do . /dev/shm/B3;done;echo $V3
1612187.89
1612188.79
printf "%d 1/100th of sec\n" $((161218879-161218789))
90 1/100th of sec
No variable substitution with a call command

No variable substitution with a call command


By : Deepak Marneni
Date : March 29 2020, 07:55 AM
this one helps. You are mixing bash variables and gnuplot variables. $F1 is a bash variable and will be substituted by bash only within your bash script. Within "statistic-file.txt", bash substitutes nothing, and gnuplot complains about the unknown $F1.
You can try to "convert" the bash variable $F1 into a gnuplot variable datafile1 like this:
code :
#!/bin/bash

F1="file_1"

gnuplot -persist << EOF 

datafile1="$F1"
call "statistic-file.txt"
plot datafile1 w lp

EOF
stats datafile1
NetworkOnMainThreadException during post method dynamic url using retrofit2.0 for variable substitution

NetworkOnMainThreadException during post method dynamic url using retrofit2.0 for variable substitution


By : D Dut
Date : March 29 2020, 07:55 AM
wish helps you For longer running task use enqueue which runs Asynchronously in the background, instead of execute which is a Synchronous process, so use
code :
 res.enqueue(new Callback<String>() {
            @Override
            public void onResponse(Call<String>call, Response<String> response) {
              // response.body(); // to get the response
            }

            @Override
            public void onFailure(Call<String>call, Throwable t) {
            }
        });
bash substitution call that increments a variable

bash substitution call that increments a variable


By : statibox
Date : March 29 2020, 07:55 AM
this one helps. I'm trying to define a bash function returning an incremented id that I can access directly using bash substitution:
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