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MySQL query to get the sum of a column


MySQL query to get the sum of a column

By : user2952792
Date : November 19 2020, 03:59 PM
To fix the issue you can do I need to get the sum of column with two conditions.i.e , Try this:
code :
SELECT Dos, 
       SUM(CASE WHEN Insurance != 'Selfpay' THEN bill_amount ELSE 0 END) Total_amount, 
       SUM(CASE WHEN Insurance = 'Selfpay' THEN bill_amount ELSE 0 END) selfpay 
FROM tableA 
GROUP BY Dos;


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MySQl Query: copy a column named 'C' from table2 to column 'C' in table1 without losing any other column data

MySQl Query: copy a column named 'C' from table2 to column 'C' in table1 without losing any other column data


By : user3452750
Date : March 29 2020, 07:55 AM
wish of those help Assuming the Table1 already contains the C column and you can Join by id:
code :
UPDATE table1 t1 JOIN table2 t2 ON t1.id = t2.id
SET t1.col1 = t2.col2, t1.col2 = t2.col2
MySQL query to convert a table into distinct column and other column count array?

MySQL query to convert a table into distinct column and other column count array?


By : erdem
Date : March 29 2020, 07:55 AM
hope this fix your issue My data table is as below:
code :
SELECT
  WEEK,
  SUM(RESULT='GOOD') As GOOD_RESULT,
  SUM(RESULT='BAD') As BAD_RESULT,
  SUM(RESULT='WORST') AS WORST_RESULT,
  COUNT(*) As TOTAL
FROM YourTable
GROUP BY
  WEEK
MySQl need to add a column to the existing query / print the group name in the added column

MySQl need to add a column to the existing query / print the group name in the added column


By : chief__brody
Date : March 29 2020, 07:55 AM
it should still fix some issue I have a query like this , You must use a case clause. Try this:
code :
SELECT us.recNo, 
       CONCAT(us.firstname, ' ',us.lastname) AS fullname, 
       max(dy.date) AS diarydate,
       case when MAX(dy.date) IS NOT NULL then 'DiaryGroup' else 'NoDiary' end as group
FROM users us LEFT JOIN diary dy ON us.recNo = dy.clientID AND dy.date >= 
       (SELECT max(DATE(dateTime)) 
       FROM `history` 
       WHERE userID=us.managerID) OR dy.date is NULL
WHERE us.managerID =  6  and us.accountStatus = 2 and us.securityGroup = 50
GROUP BY us.recNo, fullname
ORDER BY diarydate DESC, fullname
MYSQL query - simple way to return all values from one column based on a DISTINCT value in another column in the same ta

MYSQL query - simple way to return all values from one column based on a DISTINCT value in another column in the same ta


By : Venu
Date : March 29 2020, 07:55 AM
seems to work fine I'm assuming you're using php because of the debug output.
I think you just want to stack your results in an associative array where the key is the store_id. This example uses mysqli_query but you can adapt it to pdo.
code :
$results_by_store_id = array();
$rs = mysqli_query("select * from customer_per_store where store_id <> 0");
while($r = mysqli_fetch_assoc($rs)) {
    $results_by_store_id[$r['store_id']][] = $r['pid'];
}

print_r($results_by_store_id);
MySQL query with a date range selection but also need to grab the highest value of one column when another column has du

MySQL query with a date range selection but also need to grab the highest value of one column when another column has du


By : mahendra mahi
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Thank you. I have updated my answer. please check. Hope this will solve your issue. If not let me know I will update my answer.
code :
    SELECT MAX(id), item_number, style_number, date_of_entry 
  FROM import_items 
  WHERE id IN 
          (SELECT id FROM import_items where (date_of_entry >= '12/07/2016' 
                                   AND date_of_entry<='12/11/2016') 
                                   AND TRIM(style_number) != '' ) 
  GROUP BY item_number;
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