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Compiler throwing error for function return type returning structure pointer


Compiler throwing error for function return type returning structure pointer

By : Richard Peng
Date : November 19 2020, 03:59 PM
Does that help Can someone please explain why am I getting the compilation error the below code. , change
code :
( struct node *) createNode(int num)
struct node * createNode(int num)


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Returning pointer to structure to main function, getting segmentation error

Returning pointer to structure to main function, getting segmentation error


By : user1548579
Date : March 29 2020, 07:55 AM
will be helpful for those in need Your s variable is allocated on the stack, and then you are returning a pointer to it; however, when the function ends, s no longer exists and the pointer is no longer valid.
You could either dynamically allocate s and return a reference/pointer to it, or you could return a copy of s rather than a reference.
Return type of a function returning a pointer? (C++)

Return type of a function returning a pointer? (C++)


By : MonikaJag
Date : March 29 2020, 07:55 AM
around this issue In Node.h, the return type of getNext() probably needs to be Node *. You have not supplied any return type.
That would be consistent with the definition within Node.cpp. Note that Node.cpp needs to #include "Node.h" before trying to define member functions of Node.
C Compiler throwing error: called object ‘random’ is not a function or function pointer

C Compiler throwing error: called object ‘random’ is not a function or function pointer


By : Galina Petrova
Date : March 29 2020, 07:55 AM
will be helpful for those in need You have defined a variable with the same name as a function you're trying to call. This "shadows" the function and makes it impossible to call:
code :
int random;
Return value type does not match function type when returning pointer to constant getter

Return value type does not match function type when returning pointer to constant getter


By : Quarter33
Date : March 29 2020, 07:55 AM
it should still fix some issue A method with const at the end of it is a const method. It is legal to call on a const instance of the object or through a const reference to the object, and it promises that it will not change the state of the object, nor will it be the route of permission to allow others to change the state of the object (basically, it won't change the state of the object, directly or indirectly).
Your const method returns a pointer to something within the object. Within the const method, that sub-object is also const. So a pointer to it is a pointer to a const instance. You then return it as a non-const pointer, and the compiler complains.
Why does'nt the compiler throw error for not returning this pointer for a function whose return type is classname&

Why does'nt the compiler throw error for not returning this pointer for a function whose return type is classname&


By : mike
Date : March 29 2020, 07:55 AM
I hope this helps you . Why does'nt the compiler throw error for not returning this pointer for a function whose return type is classname& ,
How is the compiler treating these functions
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