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Define int-like type in C


Define int-like type in C

By : user2952644
Date : November 19 2020, 01:01 AM
Any of those help Original question was changed from 5 bits to 4, but the range 0..16 does require 5 bits, as several people commented.
You can't use a storage type smaller than char. Your problem with come with arithmetic and bit operations (eg shift), because you will have to mask off bits that are not a part of your type, and this will have to be done with (inline) functions or macros.
code :
#include <stdio.h>

#define MASK5  0x1F
#define MASKX  0xF0

typedef unsigned char u5;  // unsigned 5-bit type
typedef char s5;           // signed 5-bit type

char extend5 (char num) {
    if (num & MASKX)
        num |= MASKX;
    return num;
}

s5 mul_s5 (s5 arg1, s5 arg2) {
    return (s5)((extend5(arg1) * extend5(arg2)) & MASK5);
}

u5 mul_u5 (u5 arg1, u5 arg2) {
    return (arg1 * arg2) & MASK5;
}

int main(void)
{
    // simple example
    printf ("%2u * %2u = %2u\n", 2, 3, (unsigned)mul_u5((u5)2,  (u5)3));

    // overflow example is truncated
    printf ("%2u * %2u = %2u\n",12,23, (unsigned)mul_u5((u5)12, (u5)23));

    // signed example without extending product
    printf ("%2d * %2d = %2d\n",-2, 3, (int)mul_s5((s5)-2, (s5)3));

    // signed example with sign extension
    printf ("%2d * %2d = %2d\n",-2, 3, (int)extend5(mul_s5((s5)-2, (s5)3)));

    return 0;
}
 2 *  3 =  6
12 * 23 = 20
-2 *  3 = 26
-2 *  3 = -6


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C++ : how can I define an array type customers in a class name careercenter then define create, modify and delete in .cp

C++ : how can I define an array type customers in a class name careercenter then define create, modify and delete in .cp


By : codejagger
Date : March 29 2020, 07:55 AM
help you fix your problem The best idea would be to use one of the stl containers, std::list would be fine: http://www.cplusplus.com/reference/list/list/ . You may use associative container like std::map to access customer by its unique name.
Moreover individual customers should be notified when a company customer advertises some job (so I presume). Observer design pattern would do the trick: http://www.oodesign.com/observer-pattern.html
How to define a type that define an array of complex type in SOAP

How to define a type that define an array of complex type in SOAP


By : Sean Danaher
Date : March 29 2020, 07:55 AM
To fix this issue Finally the problem was that I was using soapenc namespace as stated in all sites, however, my actual namespace was SOAP-ENC.
Regards, Jaime
Define a type constructor to build a type lambda (partially applied type)

Define a type constructor to build a type lambda (partially applied type)


By : Giuliano Velli
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I can't seem to find a solution other than staying with a type-projection, only shorter:
code :
trait Ex[A] { type L[S <: Sys[S]] = Expr[S, A] }

def name[S <: Sys[S]](p: Proc[S]): String = 
  p.attribute[Ex[String]#L]("name").fold("<unnamed>")(_.value)
implicit class RichProc[S <: Sys[S]](val `this`: Proc[S]) extends AnyVal {
  def attrExpr[A](key: String)
                 (implicit tag: ClassTag[Expr[S, A]]): Option[Expr[S, A]] =
    `this`.attribute[({type Ex[~ <: Sys[~]] = Expr[~, A]})#Ex](key)
}

def name[S <: Sys[S]](p: Proc[S]): String = 
  p.attrExpr[String]("name").fold("<unnamed>")(_.value)
Define a variable of type 'Type' which only accepts types which are subclasses of a specific type

Define a variable of type 'Type' which only accepts types which are subclasses of a specific type


By : MOzil
Date : March 29 2020, 07:55 AM
seems to work fine I'm using C# and I have the following method in my code: , You can use generic with constraint for this purpose:
code :
public void Test<T>() where T : MyClass
{
    var type = typeof(T);
    // ...
}
How to define a user define data type in XML schema?

How to define a user define data type in XML schema?


By : Shalini Yadav
Date : March 29 2020, 07:55 AM
Does that help The way to use a common simple type for the developer id is to declare it as a named type at the beginning:
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