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c# how can i add constraint in my code


c# how can i add constraint in my code

By : user2952432
Date : November 19 2020, 01:01 AM
should help you out You should use a loop together with a counter, increment the counter every time age <= 0. At the start of the loop, check if counter is 3, then print error message and exit.
Otherwise, if everything is ok, break; from the while loop.
code :
int counter = 0;
while (true)
{
    if (counter == 3) {
        Console.WriteLine("Thank You");
        Environment.Exit(0);
    }

    age = Convert.ToInt32(Console.ReadLine());
    if (age > 0)
        break;
    counter++;
}


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Error while copying records from table1 to table 2. sqlite constraint exception error code 19 constraint failed

Error while copying records from table1 to table 2. sqlite constraint exception error code 19 constraint failed


By : Harindu Weerakkody
Date : March 29 2020, 07:55 AM
I wish this helpful for you It is actually possible to set autoincrement columns to a specific value, but only if that value does not yet exist.
It is likely that the records already exist in the RECOUNT1 table.
code :
mDb.execSQL("DELETE FROM " + TABLE_RECOUNT1);
mDb.execSQL("INSERT INTO " + TABLE_RECOUNT1 + " SELECT ...");
mDb.execSQL("INSERT OR IGNORE INTO " + TABLE_RECOUNT1 + " SELECT ...");
EF5, code first exception ONLY on first database access: "FK_x...x' is not a constraint. Could not drop constraint&

EF5, code first exception ONLY on first database access: "FK_x...x' is not a constraint. Could not drop constraint&


By : Mouss Douc
Date : March 29 2020, 07:55 AM
wish help you to fix your issue This has been driving me crazy for days. I am using vs2012, EF5 code first, sql server 2012. This is on my development machine and I get the below exception when, and ONLY when, I hit the database the very first time. If, before I run my tests, I init the database, it throws the below exception, but not thereafter. If I run my tests, the first test fails because of this exception, but all my other tests pass. If I catch the exception and ignore it, all my tests pass without error. What is frustrating, is I've defined constraints, between those two tables, but don't know where 'Users_Id' is defined. I've also tried manually deleting the tables and running the vs2012 generated sql from my DbContext to recreate the table fresh, but nothing works. Any help would be much appreciated. , This fixed it
In my DbContext
code :
protected override void OnModelCreating(DbModelBuilder modelBuilder)
      {
         Database.SetInitializer(new MigrateDatabaseToLatestVersion<Context, ContextConfiguration>());

         base.OnModelCreating(modelBuilder);
      }
public class ContextConfiguration : DbMigrationsConfiguration<Context>
   {
      public ContextConfiguration()
      {
         this.AutomaticMigrationsEnabled = true;
         this.AutomaticMigrationDataLossAllowed = true;
      }
   }
[TestInitialize]
      public override void TestInitialize()
      {
         // Force model updates.
         using (var uow = UnitOfWorkFactory.Instance.Create<UnitOfWorkCore>(DefaultConnectionString))
         {
            uow.Database.Initialize(force: false);
         }

         // begin transaction
         this.transactionScope = new TransactionScope();

         this.unitOfWork = UnitOfWorkFactory.Instance.Create<UnitOfWorkCore>(DefaultConnectionString);
      }
[TestInitialize]
      public override void TestInitialize()
      {
         // Force model updates.

         // I CHANGED TO THIS:
         Database.SetInitializer(new DropCreateDatabaseAlways<Context>());

         using (var uow = UnitOfWorkFactory.Instance.Create<UnitOfWorkCore>(DefaultConnectionString))
         {
            uow.Database.Initialize(force: false);
         }

         // begin transaction
         this.transactionScope = new TransactionScope();

         this.unitOfWork = UnitOfWorkFactory.Instance.Create<UnitOfWorkCore>(DefaultConnectionString);
      }
Failed to add the foreign key constraint. Missing index for constraint Error Code: 1822

Failed to add the foreign key constraint. Missing index for constraint Error Code: 1822


By : Jason
Date : March 29 2020, 07:55 AM
this one helps. You have a composite primary key, so you need a composite foreign key:
code :
CREATE TABLE Prerequisite_to(
    infs CHAR(4),
    course_number CHAR(3),
    PRIMARY KEY (infs,course_number),
    FOREIGN KEY (infs, course_number) REFERENCES Class(infs, course_number)
);
CREATE TABLE Classes (
    class_id int auto_increment primary key,
    infs CHAR(4) NOT NULL,
    course_number CHAR(3) NOT NULL,
    unique (infs, course_number)
);

CREATE TABLE Prerequisites (
    preresequisite_id int auto_increment primary key,
    class_id int,
    prerequisite_class_id int,
    FOREIGN KEY (class_id) REFERENCES Classes(class_id),
    FOREIGN KEY (prerequisite_class_id) REFERENCES Classes(class_id)
);
Error Code: 1822. Failed to add the foreign key constraint. Missing index for constraint 'employee_ibfk_1' in the refere

Error Code: 1822. Failed to add the foreign key constraint. Missing index for constraint 'employee_ibfk_1' in the refere


By : user2676479
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You should probably add a primary key on addressid in the Address table, this will create the index needed. In your current script there is no guarantee that addressid will be unique, hence if there would be duplicates a foreign key could never determine which row to refer to.
code :
create table address(addressId int primary key not null, city varchar(10), pincode varchar(10));
Error Code: 1822. Failed to add the foreign key constraint. Missing index for constraint 'questions_ibfk_1' in the refer

Error Code: 1822. Failed to add the foreign key constraint. Missing index for constraint 'questions_ibfk_1' in the refer


By : Sid
Date : March 29 2020, 07:55 AM
I hope this helps you . You get this error because there's no index on category_name in the category table. Change that CREATE statement as follows:
code :
create table category (
 category_id int  primary key not  null,
 category_name varchar(50) not null,
 KEY category_name_index (category_name)
 );
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