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Pass a array from one function to another


Pass a array from one function to another

By : Balázs Deák
Date : November 19 2020, 01:01 AM
seems to work fine I have this code which grab data from a xml file. I need to feed these data to a google chart which is currently in an array. I need to pass my xml values to the google chart. Can anyone help me to figure this out. The below is my code. , Change this
code :
var data = google.visualization.arrayToDataTable([
            ['Task', 'Hours per Day'],
            ['Work',     11],
            ['Eat',      2],
            ['Commute',  2],
            ['Watch TV', 2],
            ['Sleep',    7]
        ]);
var data = google.visualization.arrayToDataTable((Array.isArray(val) && val.length) ? val : [
    ['Task', 'Hours per Day'],
    ['Work',     11],
    ['Eat',      2],
    ['Commute',  2],
    ['Watch TV', 2],
    ['Sleep',    7]
]);
$(xml).find('Pie').each(function() {
    var sTitle = $(this).find('Title').text();
    var sValue = $(this).find('Value').text();

    if (!isNaN(+sValue)) {
        sValue = +sValue;
    } 

    values.push([sTitle, sValue]);
});


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pass to function: incremented integer inside array or set reset array with ternary operator or a custom function

pass to function: incremented integer inside array or set reset array with ternary operator or a custom function


By : ckjun
Date : March 29 2020, 07:55 AM
it fixes the issue Not sure that I completely understand your question, but maybe that helps you
code :
myfunction("MyID"    , arr_1[(indexes[0]++)%arr_1.length]);
0%2 = 0
1%2 = 1
2%2 = 0
3%2 = 1
...
and so on
How to allocate memory for an array of structs, then pass that array to a function, which populates the array in C

How to allocate memory for an array of structs, then pass that array to a function, which populates the array in C


By : Andrew Cammarano
Date : March 29 2020, 07:55 AM
I hope this helps you . The problem is in your for loop in main to print the deployment times, sizeof(assets) does not give you the length of the array, there is no way to get the length of an array only pointed to by a simple pointer. sizeof(assets) gives you the size of a pointer in chars, which is 8 as you're apparently working on a 64 bit platform. Simply run from 0 up to asset_size.
And why are you mallocing a new struct in read_data for each asset, just write directly into the asset array.
code :
for (int i = 0; i < size_assets; ++i)
    printf("%d\n", assets[i].deployment_time);
asset* asset_p = assets;
while (fscanf(...) != EOF) {
    asset_p->field = data;
    ...
    ++asset_p;
}
int i = 0;
while (fscanf(...) != EOF) {
    assets[i].field = data;
    ...
    ++i;
}
for (int i = 0; fscanf(...) != EOF; ++i) {
    assets[i].field = data;
    ...
}
How to pass an array of functions as argument to another function and invoke these function in the later function

How to pass an array of functions as argument to another function and invoke these function in the later function


By : Razvan Zamfir
Date : March 29 2020, 07:55 AM
Hope this helps You need add callback function in order to go to the next task, like this
code :
var async       = require('async');
var exeFunction = [];
var resArray    = [];

var addOne = function (num) {
    return function (next) {
      resArray.push(10); // or resArray.push(num)
      next(null);
    }
}

for (var i = 0; i < 10; i++) {
  exeFunction.push(addOne(i));
}

async.waterfall(exeFunction, function (err, res) {
    console.log(resArray)
})
Is Passing a Dynamically Allocated Array to a Function in C an Instance of Pass-by-value or Pass-by-reference?

Is Passing a Dynamically Allocated Array to a Function in C an Instance of Pass-by-value or Pass-by-reference?


By : Mak Lampir
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further In C, everything is passed by value. In your concrete example arr is. You don't have references like in C++ or Java.
Let's take a C++ example:
code :
void foo(int& i) {
    ++i;
}

int main() {
    int i = 1;

    foo();
}
void foo(int* i) {
    ++*i;
}

int main() {
    int i = 1;

    foo(&i);
}
How to pass a pointer array to a function as pass by reference?

How to pass a pointer array to a function as pass by reference?


By : Guru Sk
Date : March 29 2020, 07:55 AM
wish helps you When you call int *arr = new int[SIZE]; you have allocated memory to store SIZE of int and arr is pointing to this memory.
Inside addData function you call arr = new int[SIZE+1]; expecting arr to be now pointing to a memory filled with new values when the function returns. However when int *arr is passed to void addData(int *arr, int &SIZE, int data) it gets copied. The pointer variable arr has the same value as an outer variable but they are referencing different places. After arr = new int[SIZE+1]; inner variable no longer points to the same place as an outer one.
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