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java problems with variable ":"


java problems with variable ":"

By : Dan
Date : November 19 2020, 12:41 AM
should help you out i have a problem with some java code. , Change it to
code :
label820: {
    result.value = -2;
    if(a==10) { // I assume you wanted to compare a to 10 and not assign 10
        b=a;
        break label820;
    }
}


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What does "Add Variable" mean? and other Eclipse Java Build Path "what does this button do" question

What does "Add Variable" mean? and other Eclipse Java Build Path "what does this button do" question


By : Aurélio Vinícius
Date : March 29 2020, 07:55 AM
hope this fix your issue "Add variable" is used to add a JAR or directory at a location relative to a classpath variable that you have configured in your Eclipse preferences. I've used the facility when working with a team of developers sharing a related set of Eclipse projects via source control, where the projects rely on a set of JAR files on a network share that is mounted at a different location for different developers. Everyone sets the same LIB_HOME variable to point to where they have the shared folder mounted on their particular machine (e.g. L:\ on Windows, /Volumes/Libs on Mac, etc.), and the Eclipse projects then point to the required JARs relative to that variable.
java,how to consult sql lite if a value of a variable "varConsult" is in column "protocolo" in table

java,how to consult sql lite if a value of a variable "varConsult" is in column "protocolo" in table


By : Kevin Compagno
Date : March 29 2020, 07:55 AM
it fixes the issue You need to iterate inside the result set to retrive the actual data that were found:
code :
while (existetabela.next()){
 System.out.println(existetabela.getObject("protocolo"));
}
How use "LIKE" and "%" to check similarity to variable in android(Java code)

How use "LIKE" and "%" to check similarity to variable in android(Java code)


By : Alejandro Benitez
Date : March 29 2020, 07:55 AM
I wish this helpful for you In the expression 'hi' LIKE '%hi there%', it is not possible to find any characters to replace the % wildcards so that the strings would match.
You need to do the comparison the other way around, i.e., 'hi there' LIKE '%hi%':
code :
db.rawQuery("SELECT shompet FROM sentence" +
            " WHERE ? LIKE '%' || " + column + " || '%'",
            new String[] { newMessage });
Exception in thread "main" java.lang.Error: Unresolved compilation problems: The local variable xxx may not ha

Exception in thread "main" java.lang.Error: Unresolved compilation problems: The local variable xxx may not ha


By : Jonathan Hopper
Date : March 29 2020, 07:55 AM
I hope this helps . Interesting, I can see you just started to learn programming, and you are confused about the relation between programming and math.
You expect programming something like math.
code :
1500 = 3 * time
fetch data from some memory
perform simple operation (for instance math operation + - * / )
store result back to some memory
fetch values from memory "speed" and memory "time"
perform math multiply on the two values
store the result back to memory "distance"
time = distance / speed;

fetch values from distance and speed
perform math divide on the two values
store result back to time
Java "Duplicate local variable " and "cannot convert from String to Module"

Java "Duplicate local variable " and "cannot convert from String to Module"


By : Franziska Knopp
Date : March 29 2020, 07:55 AM
I wish did fix the issue.
You redefined a variable m, it is in the first line of the code and then again in the for loop: for (Module m : Boi.moduleManager.mods) {--
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