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# largest array, sorted in reverse order from the given array

By : user2952333
Date : November 19 2020, 12:41 AM
Does that help What is the largest array, sorted in reverse order from the given array?
code :
``````def findRuns(L):
start = 0
n = L[start]
for i,num in enumerate(L[1:],1):
if num <= n:
n = num
else:
start = i
n = L[start]
``````
``````In [48]: findRuns([25,28,11,10,9, 8, 23] )
Out[48]: [[25], [28, 11, 10, 9, 8], [23]]

In [49]: findRuns([25,28,11,10,9, 8,17, 23,20,19,14] )
Out[49]: [[25], [28, 11, 10, 9, 8], [17], [23, 20, 19, 14]]
``````

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## Find the largest value smaller than x in a sorted array

By : Melech Mizrachi
Date : March 29 2020, 07:55 AM
I wish this help you Use Array.BinarySearch. If the input is in the list, it will return the index, and if not then it will return the complement of the index of the first larger value. You just invert the result and subtract one to get the index of the closest smaller value.
code :
``````int[] arr = { 1, 23, 57, 59, 120 };
int index = Array.BinarySearch(arr, 109);
if (index < 0)
{
index = ~index - 1;
}
if (index >= 0)
{
var result = arr[index];
}
``````

## Algorithm that gets the largest sorted sub array from an array

By : Dharmik Jogi
Date : March 29 2020, 07:55 AM
I wish this helpful for you Your problem is known as "longest increasing subsequence".
An algorithm utilizing dynamic programming can be found here, with a good explanation. It has optimal asymptotic complexity of O(nlogn).

## how to find largest elements from the sorted array?

Date : March 29 2020, 07:55 AM
code :
``````var array1 = [2, 7, 12, 23, 40, 44, 67, 88, 102]
var array2 = [3, 12, 14, 17, 23, 40, 41, 67, 108]
var array3 = [8, 12, 23, 40, 59, 86, 119, 130]

var flatArray = array1.concat(array2).concat(array3);

flatArray.sort(function sortNumber(a, b) { return b - a; });
var maxArray = flatArray.slice(0, 5);

``````

## Getting largest k elements in an array outputted in sorted order in O(n + klogk) using heaps?

By : Elatha
Date : March 29 2020, 07:55 AM
I hope this helps . The problem with using this min-heap approach is that you have to constantly process the entire rest of the array, giving you an n factor in-front of the log k.
There is a way to reduce the work done in actually extracting the first k elements, by using a divide-and-conquer strategy similar to that of quicksort. This exponentially decreases the part of the array which has to be processed.

## Find kth largest element from a 2-d sorted array

By : César Corredera More
Date : March 29 2020, 07:55 AM
help you fix your problem If you have an n * n matrix then it is possible to do this in average time O(n * log(n) * log(n)).
What you do is break the matrix into a series of sorted arrays, then do a binary search through all of them at once. For instance suppose that n = 4 and is indexed from (0,0) to (3,3). We can break it into arrays that go down a column to the rising diagonal then turn right to finish the row. This would give us the following set of sorted arrays: