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Why can't I pass this class as a reference when returned from arithmetic operators?


Why can't I pass this class as a reference when returned from arithmetic operators?

By : WB-ZA
Date : November 19 2020, 12:41 AM
I hope this helps . You're creating arithmetic operators with a side affect... These operators shouldn't change the value of the arguments used.
And, to the answer your question, these methods return a temporary object, that can't be passed as reference to SetVarC.
code :
template<typename T = int>
inline coord<T> operator-(const coord<T>& lhs, const coord<T>& rhs)
{
    coord<T> res(lhs)
    res -= rhs;
    return res;
}

template<typename T = int>
inline coord<T> operator+(const coord<T>& lhs, const coord<T>& rhs)
{
    coord<T> res(lhs)
    res += rhs;
    return res;
}


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Arithmetic Operators vs Methods in Class Design Guidelines

Arithmetic Operators vs Methods in Class Design Guidelines


By : julienescueta
Date : March 29 2020, 07:55 AM
With these it helps In general, I think Microsoft seems to have kind of done A+B in most of their classes similar to this.
For samples, see the entire System.Windows.Media.Media3D namespace, as well as the XNA math classes. Both have point/vector/quaternion/matrices/etc, and use Class.Operator(a,b), and occasionally do c = a + b;
Is it possible to pass arithmetic operators to a method in java?

Is it possible to pass arithmetic operators to a method in java?


By : Patrick Williams
Date : March 29 2020, 07:55 AM
With these it helps No, you can't do that in Java. The compiler needs to know what your operator is doing. What you could do instead is an enum:
code :
public enum Operator
{
    ADDITION("+") {
        @Override public double apply(double x1, double x2) {
            return x1 + x2;
        }
    },
    SUBTRACTION("-") {
        @Override public double apply(double x1, double x2) {
            return x1 - x2;
        }
    };
    // You'd include other operators too...

    private final String text;

    private Operator(String text) {
        this.text = text;
    }

    // Yes, enums *can* have abstract methods. This code compiles...
    public abstract double apply(double x1, double x2);

    @Override public String toString() {
        return text;
    }
}
public String calculate(Operator op, double x1, double x2)
{
    return String.valueOf(op.apply(x1, x2));
}
String foo = calculate(Operator.ADDITION, 3.5, 2);
// Or just
String bar = String.valueOf(Operator.ADDITION.apply(3.5, 2));
How to pass arithmetic operators as function parameters in LISP?

How to pass arithmetic operators as function parameters in LISP?


By : Mubashir Lillah
Date : March 29 2020, 07:55 AM
This might help you There are two categories of Lisp dialects: Lisp-1 and Lisp-2. Lisp-1 means that functions and variables share a single namespace. Scheme is a Lisp-1. Lisp-2 means that functions and variables have different namespaces. Common Lisp is a Lisp-2. If you want to pass a function named a as an argument to another function, you must refer to it as #'a. If you have a function stored in a variable, you can use the apply function to execute it. You code should work if it is rewritten like this:
code :
(defun operation (op)
  (apply op '(3 7)))

(operation #'+)
AngularJS: Pass arithmetic operators to ng-value

AngularJS: Pass arithmetic operators to ng-value


By : Kapil Chavan
Date : March 29 2020, 07:55 AM
wish of those help 1) ngValue expects expression, but simple + sign is not a valid expression, it will give errors in the console, that is why you have to work with strings, when populating your type="radio" elements.
2) As you are dealing with strings, you have to use $parse service to evaluate this string into result.
code :
angular.module("myMdl", [])
.controller("myCtrl1", function($scope, $parse) {
  var ctrl = this;
  
  ctrl.Mdloperator = '/';
  ctrl.Number1 = 1;
  ctrl.Number2 = 2;
  
  ctrl.getValue = function(val){
   return angular.isString(val) ? $parse(val)($scope) : val;
  };
});
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js"></script>


<h1> Calculator Application </h1>

<div ng-app="myMdl" ng-controller="myCtrl1 as $ctrl">
    <br>
    Select Operator:
    <ul>
     <input ng-repeat-start="op in ['+', '-', '*', '/'] track by $index" type="radio" ng-model="$ctrl.Mdloperator" name="operator" ng-value="op" />  {{::op}} <br ng-repeat-end/>
    </ul>               
    Enter Value's: 
    <ul>
        <input type="number" ng-model="$ctrl.Number1"  /> <br>
        <input type="number" ng-model="$ctrl.Number2" /> <br>
    </ul>
    Result: <br>
    <ul>
        <input type="number" value="{{$ctrl.getValue($ctrl.Number1 + $ctrl.Mdloperator + $ctrl.Number2)}}" placeholder="Result"/>
    </ul>
</div>
Using ostream with overloading arithmetic operators for class

Using ostream with overloading arithmetic operators for class


By : MuthuMadan
Date : March 29 2020, 07:55 AM
wish of those help The overloaded operator<< takes Rational& as its argument.
So in the case of the below statements:
code :
Rational r3 = r1*r2;
cout << r3 << endl;
cout << r1*r2 << endl;
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