Unexpected PHP Parse error: (T_CONSTANT_ENCAPSED_STRING), after I moved to new server

Unexpected PHP Parse error: (T_CONSTANT_ENCAPSED_STRING), after I moved to new server

By : user2951875
Date : November 18 2020, 03:49 PM
Hope that helps This is one of most common parsing PHP errors, I have encountered it mostly due to version conflict.
The PHP version on new server may be different from old one. Most probably lower than old one. Upgrade/ Match PHP version on both servers to get rid of error.
code :

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Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting T_STRING or T_VARIABLE or '{' or '$'

Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting T_STRING or T_VARIABLE or '{' or '$'

By : user2702086
Date : March 29 2020, 07:55 AM
it fixes the issue From this Simple Dom Site , There are a few issues here I'll just correct them inline:
code :
    $sidebarFile = 'D:\xampp\htdocs\final\wordpress\sidebar.php';
    $openSidebarFile = fopen($sidebarFile,'a');
    foreach($html->find('div#sidebar') as $e)
        $html ->find('div[id=sidebar]', 0) -> innertext;
        $inputSidebar = $e->outertext;
        fwrite($openSidebarFile, "\n" .inputSidebar "\n");
Parse error - unexpected T_CONSTANT_ENCAPSED_STRING

Parse error - unexpected T_CONSTANT_ENCAPSED_STRING

By : Pady
Date : March 29 2020, 07:55 AM
With these it helps Php complains that
code :
73      'database' => 'blogtest' ,
                                 ^ this comma is missing.
Unexpected parse error T_CONSTANT_ENCAPSED_STRING

Unexpected parse error T_CONSTANT_ENCAPSED_STRING

By : Mohd82kh
Date : March 29 2020, 07:55 AM
will help you At & " you're closing your starting quote. You need to escape it with a backslash:
code :
$sql = 
"SELECT ubuser.usr_firstname, ubuser.usr_lastname, ubuser.usr_DOB,  
ubuser2_1.usr_firstname & \" \" & ubuser2_1.usr_lastname AS UBFriend,
ubFriendsLink.ub_lnkID1, ubFriendsLink.ub_lnkID2, ubuser.usr_ID, ubuser2_1.usr_ID 
FROM ubuser AS ubuser2_1 INNER JOIN (ubFriendsLink INNER JOIN ubuser 
ON ubFriendsLink.ub_lnkID1 = ubuser.usr_ID) ON ubuser2_1.usr_ID = 
ubFriendsLink.ub_lnkID2 WHERE (((ubFriendsLink.ub_lnkID1) = ".$_SESSION['usr_ID'] .")) 
OR (((ubFriendsLink.ub_lnkID2) = ".$_SESSION['usr_ID'] ."))";
Parse error unexpected t_constant_encapsed_string php

Parse error unexpected t_constant_encapsed_string php

By : Jennie Törnvi
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have a for loop to go through an array I get from a web service that are paths to images, that I want to insert into and tags and print as much as there are in the array. The problem is that I'm getting the encapsed string error and I can't see where should I correct my code. , change to this..
code :
$format.='<div class="col-sm-3 col-xs-6">
                <a href="'.$curl_odgovor_decoded[0]['slika'.$i].'" title="slika'.$i.'" data-gallery="#blueimp-gallery">
                <img class="img-responsive img-customer" src="">
                echo $format;
parse error unexpected '' '' T_CONSTANT_ENCAPSED_STRING

parse error unexpected '' '' T_CONSTANT_ENCAPSED_STRING

By : Daksh Asija
Date : March 29 2020, 07:55 AM
help you fix your problem I'm having a problem with my PHP, I'm trying to create the empty space to make it seperate with other variable, but i'm getting an parse error unexpected '' '' (T_CONSTANT_ENCAPSED_STRING), expecting ',' or ';'. , If you want to provide space then can use  
code :
echo '<span id="time1">'.$time1.'</span> - <span id="title1">'.$programme1.'&nbsp;'.$programme1a.'</span><br><br>';
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