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In Java, is it possible to override methods if return types are respectively a primitive and its wrapper class?


In Java, is it possible to override methods if return types are respectively a primitive and its wrapper class?

By : todaygadday
Date : November 18 2020, 03:49 PM
wish help you to fix your issue You can only return same type or a sub-class of the parent's return type and its known as Co-Variant return types.
The compiler lets you auto-box and unbox between primitives and wrappers but this doesn't make one a sub-class of the other. Primitives are not classes and cannot be used in the way you have.
code :


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Performance: typedef vs wrapper class for primitive types?

Performance: typedef vs wrapper class for primitive types?


By : meenakshi muwal
Date : March 29 2020, 07:55 AM
will be helpful for those in need Actually, there are two reasons this could conceivably be slower.
First, there's no way to create an uninitialized NodeId. Normally, that's a good thing. But imagine you have code like this:
code :
NodeId nodeid;
foo.initializeNodeId(&nodeid);
#if __cplusplus > 201000L
#define CONSTEXPR_ constexpr
#else
#define CONSTEXPR_
#endif

class NodeId
{
    int value;
public:
    struct Uninitialized {};
    CONSTEXPR_ NodeId() : value(-1) {}
    CONSTEXPR_ NodeId(Uninitialized) {}      
    CONSTEXPR_ NodeId(int value) : value(value) {}
    CONSTEXPR_ operator int() const {return value;}
    CONSTEXPR_ bool isValid() const {return value != -1;}
    //...
};
NodeId nodeId(NodeId::Uninitialized());
foo.initializeNodeId(&nodeid);
myClassTemplate<NodeId(3)> c;
int x = 3;
x += NodeId(1);
Why do two methods with signature (primitive, wrapper) and (primitive, primitive) cause the method call (wrapper, primit

Why do two methods with signature (primitive, wrapper) and (primitive, primitive) cause the method call (wrapper, primit


By : cberry
Date : March 29 2020, 07:55 AM
Hope this helps If you enjoy riveting reading, here is the relevant portion of the Java Language specification that describes how methods are resolved.
But basically your third argument can be interpreted as a primitive or an autoboxed wrapper, and the compiler can't figure out what you want. Both methods are "maximally specific" to use the JLS terminology.
In Java, do operators perform identically on primitive types and primitive wrapper classes?

In Java, do operators perform identically on primitive types and primitive wrapper classes?


By : May Ben-Arie
Date : March 29 2020, 07:55 AM
it fixes the issue Equality operators (== and !=) are not reliable when working with wrapper classes.
First, generally they compare object references, not object values. For example:
code :
Integer a = new Integer(24);
Integer b = new Integer(24);
System.out.println(a == b); // Prints false
System.out.println(a != b); // Prints true
Integer a = 24;
Integer b = 24;
System.out.println(a == b); // Prints true
System.out.println(a != b); // Prints false
Does the Java JLS specify promotion of primitive wrapper types?

Does the Java JLS specify promotion of primitive wrapper types?


By : Anshuman Singh
Date : March 29 2020, 07:55 AM
hop of those help? This is actually binary numeric promotion (JLS, Section 5.6.2).
Wrapper around Java primitive types

Wrapper around Java primitive types


By : JHan
Date : March 29 2020, 07:55 AM
help you fix your problem Why always data needs to be converted into bytes for serialization/de-serialization?
The objective of serialization is to send data to somewhere outside your software (your hard drive or other software somewhere). Those processes will need a universal low-level data representation such as bytes to be transported.
code :
private static final long serialVersionUID = 3770035753852147836L;
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