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# Implement an algorithm to delete a node in the middle of a single linked list, given only access to that node

By : ankbits
Date : November 18 2020, 03:49 PM
wish helps you Example input: the node ‘c’ from the linked list a->b->c->d->e Result: nothing is returned, but the new linked list looks like a->b->d->e , In C++, the code you wrote would look like this:
code :
``````bool deleteNode(LinkedListNode* n) {
if (n == null || (*n).next == null) {
return false; // Failure
}
(*n).data = (*next).data;
(*n).next = (*next).next;
return true;
}
``````
``````LinkedListNode* listNode = new LinkedListNode();
deleteNode(&listNode);
``````
``````*n = *next;
``````

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## Delete a node in the middle of a singly linked list given only the node. C++

By : user3431862
Date : March 29 2020, 07:55 AM
will be helpful for those in need Before I submit my code here I want to know if my idea is correct, as I already the "correct" answer to this problem. , You're right.
Let's say the Node to delete is delNode.

## using ref to delete Node in the middle of a linked list, given only access to that node

By : Mark Harris
Date : March 29 2020, 07:55 AM
hop of those help? I have the solution. So I do not need help, but I have a question. This code works: , When you call
code :
``````list.Delete(ref list.head.next.next);
``````
``````list.Delete(ref n);
``````
``````list.Delete(ref list.head.next.next);
``````
``````list.head.next.next = list.head.next.next.next;
``````
``````Node n = list.head.next.next;
list.Delete(ref n);
``````
``````Node n = list.head.next.next;
n = n.next;
``````

## Delete a Node in the Middle of a linked list, Given only access to that Node. - Python

By : Wilson Liu
Date : March 29 2020, 07:55 AM
I hope this helps . Right off the bat, it looks like you are adding the data from your middle node mid, rather than the node itself into the head position. When you try to delete mid, you need to find the node in the linked list that looks like mid since it is not the exact same node.
Alternatively, you can choose to add your Node called mid, by creating a new insert function that takes a Node instead of data.

## Deleting a middle node from a single linked list when pointer to the previous node is not available

By : J.D.
Date : March 29 2020, 07:55 AM
should help you out It's definitely more a quiz rather than a real problem. However, if we are allowed to make some assumption, it can be solved in O(1) time. To do it, the strictures the list points to must be copyable. The algorithm is as the following:
We have a list looking like: ... -> Node(i-1) -> Node(i) -> Node(i+1) -> ... and we need to delete Node(i).

## Delete the last node of a single linked list using the single pointer to start node

By : Jake
Date : March 29 2020, 07:55 AM
like below fixes the issue Yes. It is possible to delete the last node of a singly linked list, starting from the first node.
Try the following code,