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How to use regex in bash for selecting a string between double quotes?


How to use regex in bash for selecting a string between double quotes?

By : Chris Hong
Date : November 18 2020, 03:49 PM
seems to work fine You could use the below regex which matches the corresponding TYPE only if the double quotes contain all the characters you mentioned . That is, atleast a character, atleast a number, atleast a special character.
code :
grep -oP 'TYPE_[A-Z]\s*=\s*"(?=[^"]*[A-Za-z])(?=[^"]*\d)(?=[^"]*[^"\w])[\W\w]*?"' file
$ cat ri
TYPE_A = "1" AND TYPE_B = "6" AND TYPE_C = "8755asd-"
TYPE_A = "1" AND TYPE_B = "6" AND TYPE_C = "875d"
TYPE_A = "1" AND TYPE_B = "6" AND TYPE_C = "asd-"
TYPE_A = "1" AND TYPE_B = "6" AND TYPE_C = "875-"
$ grep -oP 'TYPE_[A-Z]\s*=\s*"(?=[^"]*[A-Za-z])(?=[^"]*\d)(?=[^"]*[^"\w])[\W\w]*?"' ri
TYPE_C = "8755asd-"


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java - Regex to split a string using spaces but not considering double quotes or single quotes

java - Regex to split a string using spaces but not considering double quotes or single quotes


By : Gregg Rossman
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I want to split a string using spaces but not considering double quotes or single quotes. , This regex passes your test:
code :
" (?=(([^'\"]*['\"]){2})*[^'\"]*$)"
String s = "It is a \"beautiful day\"'but i' cannot \"see it\"";
String[] parts = s.split(" (?=(([^'\"]*['\"]){2})*[^'\"]*$)");
for (String part : parts)
    System.out.println(part);
It
is
a
"beautiful day"'but i'
cannot
"see it"
regex to count number of single quotes in a string excluding 2 consecutive double quotes

regex to count number of single quotes in a string excluding 2 consecutive double quotes


By : amr
Date : March 29 2020, 07:55 AM
wish of those help You can replace all ''|[^'] in your string. It will replace all 2 single quotes and everything else but a single quote.
Example:
code :
int count2 = string.replaceAll("''|[^']", "").length();
RegEx for selecting WORD when it's not between double-quotes

RegEx for selecting WORD when it's not between double-quotes


By : Ceyhun Karimli
Date : March 29 2020, 07:55 AM
will help you What is the appropriate RegEx ( javascript ) for selecting 'and' when it's not between double-quotes. like below: , Try this it works like a charm
and(?=[^"]*("[^"]*"[^"]*)*$)
How to replace double quotes with single quotes inside of a string using regex?

How to replace double quotes with single quotes inside of a string using regex?


By : Terry MacG
Date : March 29 2020, 07:55 AM
may help you . In general, it can't be done because your content is ambiguous. Consider:
code :
{
  "one": "some text here",
  "two": "some ", "three": " text here"
}
bash variable string with quotes and double quotes

bash variable string with quotes and double quotes


By : Courtney
Date : March 29 2020, 07:55 AM
hope this fix your issue I need to store a string in a variable on bash. , Not really sure, but I think you can try with read, for example:
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