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Why does this fail: `function log(){console.log.apply(null,arguments);}`


Why does this fail: `function log(){console.log.apply(null,arguments);}`

By : serene
Date : November 18 2020, 03:49 PM
may help you . I'm trying to wrap console.log to make it shorter: , I've always seen it as:
code :
function log(){console.log.apply(console,arguments);}


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JS: .apply(null, arguments) -- Why is my function called once, whilst console.log called many times?

JS: .apply(null, arguments) -- Why is my function called once, whilst console.log called many times?


By : MonkeyNut
Date : March 29 2020, 07:55 AM
should help you out console.log isn't called for each argument. It is just a function that does something with each of the arguments it is passed. It only gets invoked once.
code :
console.log("Hello there!","Hi!","Hello!!", "Testing");
console.log("Hello there!");
console.log("Hi!");
console.log("Hello!!");
console.log("Testing");
logIt("Hello there!","Hi!","Hello!!", "Testing");
Why does var a = ...arguments fail, if console.log(...arguments) is OK?

Why does var a = ...arguments fail, if console.log(...arguments) is OK?


By : Martin Ngambi
Date : March 29 2020, 07:55 AM
will be helpful for those in need The two applications of the spread syntax are:
turn items of an iterable value into arguments of a function call turn items of an iterable into elements of an Array
code :
function fn() {
    var a = [...arguments];
}
Why call to Function.apply.bind(fn, null) calls `fn.apply`, and not `Function.apply`?

Why call to Function.apply.bind(fn, null) calls `fn.apply`, and not `Function.apply`?


By : user1824506
Date : March 29 2020, 07:55 AM
like below fixes the issue Let's split it into parts, first of all, bind():
Why do I need to pass null as an argument in function.apply(null, arguments)?

Why do I need to pass null as an argument in function.apply(null, arguments)?


By : user2382601
Date : March 29 2020, 07:55 AM
I hope this helps . The first argument of apply is the this object. You don't have to pass null, you could pass this or any other object as well, but you can't just pass arguments by itself because then arguments will become your this object in the function and name won't get a value.
Note that, for this example, you could just call fun(name) instead of fun.apply(null, arguments).
How to apply colors to console.log when using multiple arguments?

How to apply colors to console.log when using multiple arguments?


By : Raph Wu
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I'm trying to style the output of my console.log() to make my application errors stand out. , You add text in first argument after %c using template literals
code :
var text = "Hello World";
var style = "background: #222; color: #bada55";
console.log(`%c${text}`, style);
var text = "Hello World";
var style = "background: #222; color: #bada55";
console.log('%c' + text, style);
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