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Name conflict between member function and class name


Name conflict between member function and class name

By : Reakins
Date : November 18 2020, 11:13 AM
may help you . There are a few ways to disambiguate a base class hidden by a method name.
code :
typedef Move::Move Move_Base; // 1. the LHS of :: operator ignores functions
using typename Move::Move; // 2. non-template "typename" avoids constructor
typedef class Move Move_Base; // 3. elaborated type specifier
typedef ::Move Move_Base; // 4. namespace qualification (as mentioned)


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Is there any conflict for Member Class Object?

Is there any conflict for Member Class Object?


By : user2093194
Date : March 29 2020, 07:55 AM
wish help you to fix your issue The code, at first glance, seems technically correct.
However, without any explanation of your problem, or what you're trying to achieve, that's about all I can say.
Javascript class member function calling member function by setInterval, couldn't access member variable

Javascript class member function calling member function by setInterval, couldn't access member variable


By : Alrote
Date : March 29 2020, 07:55 AM
I hope this helps . setInterval() doesn't work with this. See here: https://developer.mozilla.org/en-US/docs/Web/API/WindowTimers/setInterval#The_this_problem
code :
function job_queue(){
    this.job = null;
    this.pointer = this.job;
    this.job_dispatcher = null; 
    this.length = 0;
}
job_queue.prototype.add_job = function( job ){
    if( this.job == null ){
        console.log('1st');
        this.job = {
            job:job,
            next:null
        };
        this.pointer = this.job;
        this.length = 1;
    }else{
        console.log('2nd');
        this.pointer.next = { 
            job:job,
            next:null
        };
        this.pointer = this.pointer.next;
        this.length++;
    }
};

job_queue.prototype.event_handler = function(){
        
        if( typeof this.job['job'] == 'undefined'){
            console.log('??');
        }
        if( this.job.job != null ){
            console.log('hi');
            this.job.job();
            this.job = this.job.next();
        }

}

job_queue.prototype.start_dispatch = function(){
    var self = this;
    if( this.job_dispatcher == null ){
        console.log( this.event_handler );
        this.job_dispatcher = setInterval( function(){self.event_handler()},1000);
    }
}



var jq = new job_queue();
function a(){
    console.log('hi');
};
function b(){
    console.log('hi2');
}
jq.add_job(a);
jq.add_job(b);
jq.add_job(a);
jq.start_dispatch();
Invalid use of non-static member function - Class Member Function Calling Another Class Member Function

Invalid use of non-static member function - Class Member Function Calling Another Class Member Function


By : Kay Lee
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further void(*task_main)() is expecting a pointer to a function. You attempt to feed it void otherMain(); which is a class method and has a hidden this parameter.
This stuff gets a little whacky. Here is a great write-up on some of the badness and how to avoid it.
code :
class taskRunner
{
public:
    virtual execute() = 0;
    static void task_runner(void * userparam)
    {
        taskRunner* task = (taskRunner*)userparam;
        task->execute();
    }
};
void otherMain()
{
    printf("Hello multitasking world!"); 
    yield(); // a free function that calls into the system's TaskManager to preempt
}
Parameter name conflict with class member

Parameter name conflict with class member


By : Charles
Date : March 29 2020, 07:55 AM
I think the issue was by ths following ,
Is it possible to refer to Param parameter to resolve this issue and don't needs to rename the Param?
class within a class,conflict of same data member in both these classes

class within a class,conflict of same data member in both these classes


By : Roman Sevtsov
Date : March 29 2020, 07:55 AM
it helps some times Directly accessing b, is equivalent to this.b. In that context, this reference holds reference to the inner class instance. You need a reference to the enclosing instance, to access it's instance variable. Which you can do using A.this. So, to access b of class A, you can use A.this.b:
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