Extract DateTime from the string

Extract DateTime from the string

By : Chris
Date : November 18 2020, 11:13 AM
help you fix your problem I have a string below. , Use this regex:
code :
Regex regex = new Regex(@"\d{4}-\d{2}-\d{2}_\d{2}-\d{2}-\d{2}");
var v = s.Split('_');
Console.WriteLine(string.Join("_", new string[] {v[0],v[1]}));

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Best way to extract datetime from string in python

Best way to extract datetime from string in python

By : user3172111
Date : March 29 2020, 07:55 AM
hop of those help? From python time to age part 2, timezones:
code :
from email import utils
utils.parsedate_tz('Fri, 10 Jun 2011 11:04:17 +0200 (CEST)') 
utils.parsedate_tz('Fri, 10 Jun 2011 11:04:17 +0200')
utils.parsedate_tz('Fri, 10 Jun 2011 11:04:17')
(2011, 6, 10, 11, 4, 17, 0, 1, -1, 7200)
(2011, 6, 10, 11, 4, 17, 0, 1, -1, 7200)
(2011, 6, 10, 11, 4, 17, 0, 1, -1, None)
How to extract datetime string SQL Server?

How to extract datetime string SQL Server?

By : Sri
Date : March 29 2020, 07:55 AM
wish helps you Your problem is a bit tricky, because the default formats which CONVERT() offers do not match your expected output. However, format style 120 has the following format:
code :
yyyy-mm-dd hh:mm:ss
SELECT SUBSTRING(CONVERT(VARCHAR, yourDateColumn, 120), 1, 16)
Extract DateTime from a string in R

Extract DateTime from a string in R

By : Nagi
Date : March 29 2020, 07:55 AM
around this issue You are right that you should extract the character form of the datetime first. Here is a method that works with that format. It's just using a regular expression and matching 4 digits, then groups of two digits separated by -, T and : where appropriate. You can then use lubridate::ymd_hms as an alternative to as.Date, since it's a good Swiss army knife at different date formats.
code :
string <- "<13>1 2018-04-18T10:29:00.581243+10:00 KOI-QWE-HUJ vmon 2318 - -  Some Description..."
string %>%
  str_extract("\\d{4}-\\d{2}-\\d{2}T\\d{2}:\\d{2}:\\d{2}") %>%
#> [1] "2018-04-18 10:29:00 UTC"
Extract DateTime from JSON string

Extract DateTime from JSON string

By : user1438035
Date : March 29 2020, 07:55 AM
will be helpful for those in need I have a string: , You have to deserialize it to collection of DateTime, e.g.:
code :
var val = JsonConvert.DeserializeObject<List<DateTime>>(myJson);
Extract datetime from string in T-SQL

Extract datetime from string in T-SQL

By : user1937693
Date : March 29 2020, 07:55 AM
wish helps you If the final parameter of SUBSTRING is longer than the remaining part of the string, the entire remaining string will be returned. So just change your last parameter.
code :
convert (datetime, substring(MD_SIGNATURE, charindex('/', MD_SIGNATURE,0)-2, LEN(MD_SIGNATURE)),105) as MD_SIGN_DATE
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