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Unscoped enumerators within a class definition


Unscoped enumerators within a class definition

By : user2951443
Date : November 18 2020, 11:13 AM
fixed the issue. Will look into that further As known, static data members shall not be defined in the class definition: , [class.mem]/p1:
code :


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Delphi: Using Enumerators to filter TList<T: class> by class type?

Delphi: Using Enumerators to filter TList<T: class> by class type?


By : Ashok
Date : March 29 2020, 07:55 AM
wish helps you You don't show it here, but the problem probably lies in the implementation of GetCurrent.
While the compiler accepts something like
code :
result := FShapeList[FIndex];
result := T(FShapeList[FIndex]);
C++11 Accessing Unscoped Enumerators with Qualified Name

C++11 Accessing Unscoped Enumerators with Qualified Name


By : wonderfulman
Date : March 29 2020, 07:55 AM
around this issue The quote you are looking for from the draft C++11 standard is from section 5.1 Primary expressions which in paragraph 10 says:
code :
enum direction { left='l', right='r' };

void g() {
   direction d; // OK
   d = left; // OK
   d = direction::right; // OK
}
Conceptualizing Enumerators and Lazy Enumerators in Ruby

Conceptualizing Enumerators and Lazy Enumerators in Ruby


By : user3687729
Date : March 29 2020, 07:55 AM
I hope this helps . Enumerator#lazy allows you to effectively create a chain of enumerable operations which are applied to each value as it's iterated from the enumerable. By comparison, normal enumerators perform each operation to all the values in the enumerable, then pass the result down the chain to the next operation in the chain. You can think of lazy enumerators as "depth-first" operations, and normal enumerators as "breadth-first" operations.
Normal enumerators return the result of the enumeration:
code :
> (1..10).select(&:odd?)
 => [1, 3, 5, 7, 9]
> (1..10).select(&:odd?)
 => [1, 3, 5, 7, 9]

> (1..10).select(&:odd?).map {|v| v * 2 }
 => [2, 6, 10, 14, 18]
> (1..10).lazy.select(&:odd?)
 => #<Enumerator::Lazy: #<Enumerator::Lazy: 1..10>:select>
> (1..10).lazy.select(&:odd?).map {|v| v * 2 }
 => #<Enumerator::Lazy: #<Enumerator::Lazy: #<Enumerator::Lazy: 1..10>:select>:map>
> (1..10).lazy.select(&:odd?).map {|v| v * 2 }.next
 => 2
What is the correct syntax to call a enum class enumerators that are inside a templatized class?

What is the correct syntax to call a enum class enumerators that are inside a templatized class?


By : kirtana
Date : March 29 2020, 07:55 AM
it helps some times I can't figure out how to access the enum class enumerators, either as a returning value or just a value, from a templatized class. As you can see in the following example I'm totally clueless. I've googled over the error messages with no luck. , You need to help compiler telling that Value is typename:
code :
template<int Val>
typename C<Val>::Values C<Val>::Get() 
C<0>::Values values;
In C++14, in which scope are unscoped enumerators of redeclared enumerations declared?

In C++14, in which scope are unscoped enumerators of redeclared enumerations declared?


By : daniel ianosi
Date : March 29 2020, 07:55 AM
help you fix your problem The enumeration E is declared within the namespace N, even though its definition is set within the global namespace. As such, it can only be accessed in the scope of N.
The bar function should then be defined as:
code :
int bar() {
    return int(N::A);
    //SAME AS --> return int(::N::A);
}
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