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understanding break statement and handling it for existing code


understanding break statement and handling it for existing code

By : Shivang Parekh
Date : November 18 2020, 11:13 AM
I wish this help you In the below example, i have problem in handling the break statement. For country = US, somearray will be of length one only. but in case of "DE", length is more than one. but given program, since break statement is used to get out after processing 1st row, it will not suite for DE country since DE country has more than one rows Since re- using is a better way, checking if there is someway i can re use the same logic for country =DE as well
code :
 if(country = "US" || country = "DE")
        {

            for(int i = 0; i < somearray.length(); i++)
            {

                if( (payment == "USD") )
                {
                    if(amount > 0)
                    {
                        //do something  
                    }

                    if( balance.is_positive())
                    {
                        // do something
                    }
                  if(somearray.length()==1)  // as per Your requirement country **us** has **length 1** ,in this can break the loop 
                    {break;}
                }
            }
        }


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Why does this event handling code for ender break when I try to clean it up some?

Why does this event handling code for ender break when I try to clean it up some?


By : fafaxa
Date : March 29 2020, 07:55 AM
seems to work fine This is the code that works properly: , Shouldn't the following line
code :
e.target = e[(e.target ? e.target : (e.srcElement || document))];
e.target = e[e.target ? 'target' : (e.srcElement ? 'srcElement' : 'document')];
Existing code has no line break

Existing code has no line break


By : New2Python
Date : March 29 2020, 07:55 AM
like below fixes the issue Try using Code Beautifier. You input the code and it formats it for you. There are many other sites like this one so check around and see which one you like best.
If you want to use a Sublime Text plugin, try CSS Format by mutian.
Understanding control flow of nested for loops sans break statement

Understanding control flow of nested for loops sans break statement


By : Rodolpho Alves
Date : March 29 2020, 07:55 AM
like below fixes the issue Looping through item.iteritems() goes through every key, value pair in the dictionary, so you are printing the same ID for every pair. You don't need the inner loop at all. Try this:
code :
for index, item in enumerate(res):
    print index,item
    id = item.get('id')
    print id
    video_asset_ids.append(id)
How to break part of code using label and break statement in JavaScript?

How to break part of code using label and break statement in JavaScript?


By : Walid Said
Date : March 29 2020, 07:55 AM
To fix the issue you can do No need to use break statement here. Put if condition like this. Every time the index value check it is lesser than parseInt(searchLimit.val()). if it is not it exit the if statement.
code :
if ( index < parseInt(searchLimit.val()) ) {

 outputTable: {
            output += '<tr>';
            output += '<td>' + index + '</td>';

            for ( var j = 0; j < data[i].length; j++ ) {
                output += '<td>' + data[i][j] + '</td>';
            }

            output += '</tr>';

            index++;
        }
}
if break is last statement in try block then compiled code not having break

if break is last statement in try block then compiled code not having break


By : Yury Chernushenko
Date : March 29 2020, 07:55 AM
it helps some times My Test program. , Just tried your code with a "magic" addition:
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