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writing a re usable each function that iterates through all elements


writing a re usable each function that iterates through all elements

By : user2951420
Date : November 18 2020, 11:13 AM
I think the issue was by ths following , Well I'll try making my answer more clear than my question ,
first of all , WHAT WAS MY PROBLEM :
code :
return this.each(function(){

                $(this).callsomefunction();
                // call some more functions
                // some more set of instructions
        });
$(this).callsomefunction();
function get_prop(current){
            var current_src = current.attr('src');
            if ($.inArray(current_src , src_storage) === -1) {
                src_storage.push(current_src);
            }
            return src_storage;
        }
var execute_function = function(element , function_name){
            element.each(function(){
                val = function_name;
            });
            return val;
        }
return this.each(function(){
                store_val = execute_function($(this) , get_prop($(this)));
                store_val_length = store_val.length;
                $(this).removeAttr('src');
                new_src = generate_src();
                $(this).attr('src' , new_src);           
        });
var execute_function = function(element , function_name){
            element.each(function(){
                val = function_name;
            });
            return val;
        }


        return this.each(function(){

                store_val = execute_function($(this) , get_prop($(this)));
                store_val_length = store_val.length;
                $(this).removeAttr('src');
                new_src = generate_src();
                $(this).attr('src' , new_src);           
        });

        // function to check for images that maybe repeated .
        function get_prop(current){
            var current_src = current.attr('src');
            if ($.inArray(current_src , src_storage) === -1) {
                src_storage.push(current_src);
            }
            return src_storage;
        }


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TDD - writing tests for a method that iterates / works with collections

TDD - writing tests for a method that iterates / works with collections


By : Adrian Alejandre
Date : March 29 2020, 07:55 AM
around this issue If find() is working, then it should return the index of the first element that matches the predicate, right?
So you'll need a test for the empty list case, and one for the no-matching elements case, and one for a matching element case. I would find that sufficient. In the course of TDDing find() I might write a special first-element-passes case, which I could fake easily. I would probably write:
code :
emptyListReturnsMinusOne()
singlePassingElementReturnsZero()
noPassingElementsReturnsMinusOne()
PassingElementMidlistReturnsItsIndex()
jquery each iterates even if no elements found

jquery each iterates even if no elements found


By : Raquel Rivera
Date : March 29 2020, 07:55 AM
To fix this issue each iterates over the length of the collection. When the length is 0, each will successfully call the function 0 times and return the empty collection.
So, if the function is being called, the selector is matching something.
writing a class that iterates over a hash of hashes

writing a class that iterates over a hash of hashes


By : Joel Aguero
Date : March 29 2020, 07:55 AM
should help you out All you need is a method, not a class. Here are a couple of approaches you could use.
code :
def numbers(h)    
  Hash[h.map { |k,v| [k, v[:number]] }]
end

h = { :a => {:number => 1, :color => "blue", :language => "english" },
      :b => {:number => 2, :color => "red",  :language => "english" } }

numbers(h)
  #=> {:a=>1, :b=>2}
def numbers(h)    
  h.map { |k,v| [k, v[:number]] }.to_h
end
def numbers(h)    
  h.each_with_object({}) { |(k,v),g| g[k] = v[:number] }
end
JavaScript iterates through only the first four elements

JavaScript iterates through only the first four elements


By : user3782675
Date : March 29 2020, 07:55 AM
This might help you i < $(".avatar").length - 1 is wrong as you are omitting the last item in the array. The array indexes are from 0 to length - 1, since you are doing i < length - 1 your loop executes from 0 to 2(length is 4 so i < 4-1) omitting the last element at index 3.
You could use
code :
$(".avatar").each(function () {
    if (this.naturalWidth > this.naturalHeight) {
        $(this).addClass("landscape");
    }
})
for (var i = 0; i < $(".avatar").length; i++) {
    //your code
}
While loop only iterates twice through an array with 4 elements

While loop only iterates twice through an array with 4 elements


By : Madhur Trivedi
Date : March 29 2020, 07:55 AM
hope this fix your issue , MSDN says that
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