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JavaScript partially applied function - How to bind only the 2nd parameter?


JavaScript partially applied function - How to bind only the 2nd parameter?

By : leandromonaco
Date : November 18 2020, 11:13 AM
this one helps. Of course you can do it. Here's an ES6 solution using the spread operator (...), since it's a bit more compact.
code :
// Bind arguments starting after however many are passed in.
function bind_trailing_args(fn, ...bound_args) {
    return function(...args) {
        return fn(...args, ...bound_args);
    };
}
// Bind arguments starting with argument number "n".
function bind_args_from_n(fn, n, ...bound_args) {
    return function(...args) {
        return fn(...args.slice(0, n-1), ...bound_args);
    };
}
// ES5 version: construct arguments lists yourself
function bind_trailing_args(fn) {
    var bound_args = [].slice.call(arguments, 1);
    return function() {
        var args = [].concat.call(arguments, bound_args);
        return fn.apply(this, args);
    };
}
var addThree = bind_trailing_args(add, 3);
addThree(1) // calls add(1, 3)


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Is it possible to create a partially applied function with named parameter?

Is it possible to create a partially applied function with named parameter?


By : YTC
Date : March 29 2020, 07:55 AM
will be helpful for those in need This function is provided , As noted by Travis this works:
code :
def foo( a: String = "bar", b: Int = 1, c: String = "default" ): String = s"$a$b$c"                                                
val fooc = (c: String) => foo(c = c)            
fooc("myc")
//> res0: String = bar1myc        
Bind class instance for partially applied functions

Bind class instance for partially applied functions


By : GGCoolP
Date : March 29 2020, 07:55 AM
This might help you To add to what swizard said (which is correct), one way to check what the type signature of a type class function is once it's been specialized to a particular instance is to write it out and see if psci agrees:
code :
> :type bind :: forall r a b. (r -> a) -> (a -> r -> b) -> (r -> b)
forall r a b. (r -> a) -> (a -> r -> b) -> r -> b
> :type bind :: forall r. r -> r
Error found:
[...]
   Could not match type [...] with [...]
[...]
Is it possible to have a partially applied function parameter as a vararg in Scala?

Is it possible to have a partially applied function parameter as a vararg in Scala?


By : אופק דוד
Date : March 29 2020, 07:55 AM
wish help you to fix your issue What immediately comes to mind is that not every Condition is on a single column. E.g. consider "all columns are equal" or And of two conditions on different columns. So we could change the design slightly:
code :
trait Condition extends Serializable {
    def isTrue(row: Row): Boolean
}

trait SingleColumnCondition extends Serializable {
    def value(row: Row, column: String): String = row.getAs[String](column)
    def apply(column: String): Condition
}
case class List(values: String*) extends SingleColumnCondition {
    // requires Scala 2.12 to define a Condition by a lambda
    override def apply(column: String) = row => values.contains(value(row, column))
}

case class And(conditions: Condition*) extends Condition {
    override def isTrue(row: Row): Boolean = conditions.forall(_.isTrue(row))
}

case class SingleColumnAnd(conditions: SingleColumnCondition*) extends SingleColumnCondition {
    override def apply(column: String) = And(conditions.map(_(column))
}
object And {
    def apply(conditions: SingleColumnCondition*)(implicit d: DummyImplicit): SingleColumnCondition =
        SingleColumnAnd(conditions: _*)
}
redundant parameter type info in partially applied function definition

redundant parameter type info in partially applied function definition


By : Simon
Date : March 29 2020, 07:55 AM
may help you . First of all, to avoid confusion between "def test" and "val test", let's write:
Missing parameter type for expanded function while creating partially applied function

Missing parameter type for expanded function while creating partially applied function


By : אברהם ברדה
Date : March 29 2020, 07:55 AM
To fix this issue As you have discovered, you need to give the compiler a bit more information about the types before it can work out the type of foo. You can either specify the argument types:
code :
val foo = wrap(_: String)("Hello")(_: String)
val foo: (String, String) => String = wrap(_)("Hello")(_)
val foo = wrap(_: String)("Hello")(_) // Does not compile
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