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Java Compiling Pattern in between two Strings (Dynamic)


Java Compiling Pattern in between two Strings (Dynamic)

By : user2951351
Date : November 18 2020, 01:01 AM
Any of those help You have a space after \"participantIdentities\": in your regex but you do not in your data.
code :


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Compiling dynamic HTML strings from database

Compiling dynamic HTML strings from database


By : kunal gupta
Date : March 29 2020, 07:55 AM
Does that help ng-bind-html-unsafe only renders the content as HTML. It doesn't bind Angular scope to the resulted DOM. You have to use $compile service for that purpose. I created this plunker to demonstrate how to use $compile to create a directive rendering dynamic HTML entered by users and binding to the controller's scope. The source is posted below.
demo.html
code :
<!DOCTYPE html>
<html ng-app="app">

  <head>
    <script data-require="angular.js@1.0.7" data-semver="1.0.7" src="https://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.js"></script>
    <script src="script.js"></script>
  </head>

  <body>
    <h1>Compile dynamic HTML</h1>
    <div ng-controller="MyController">
      <textarea ng-model="html"></textarea>
      <div dynamic="html"></div>
    </div>
  </body>

</html>
var app = angular.module('app', []);

app.directive('dynamic', function ($compile) {
  return {
    restrict: 'A',
    replace: true,
    link: function (scope, ele, attrs) {
      scope.$watch(attrs.dynamic, function(html) {
        ele.html(html);
        $compile(ele.contents())(scope);
      });
    }
  };
});

function MyController($scope) {
  $scope.click = function(arg) {
    alert('Clicked ' + arg);
  }
  $scope.html = '<a ng-click="click(1)" href="#">Click me</a>';
}
Java pattern contain all strings in the array

Java pattern contain all strings in the array


By : user3037050
Date : March 29 2020, 07:55 AM
I wish this help you I want to check one long string contain multiple string. , You don't need a regex for that purpose.
Use String#contains:
code :
public boolean checkContainsAll(String sentence, String[] words) {
    for(String word : words) {
        if(!sentence.contains(word)) {
            return false;
        }
    }
    return true;
}
String[] words = {"GAGGAG", "AGGAC"};
String sentence = "GAGGAGGTC";
if(checkContainsAll(sentence, words)) {
    System.out.println("The sentence " + sentence + " contains all words");
} else {
    System.out.println("The sentence " + sentence +" does not contain all words.");
}
public boolean checkContainsAll(String sentence, String[] words) {
    for(String word : words) {
        if(!sentence.contains(word)) {
            return false;
        }
        sentence = sentence.replace(word, "");
    }
    return true;
}
Splitting strings & Pattern matching in Java

Splitting strings & Pattern matching in Java


By : mariaalston
Date : March 29 2020, 07:55 AM
wish helps you I have a following String: , Just try this regexp:
code :
(K)([^P]|$)
\1\n\2
"MYLMFILLAAGCSKMYLLFINNAARPFASSTKAASTVVTPHHSYTSKPHHSTTSHCKSSDK"
    .subst("(K)([^P]|$)", "\1\n\2").split("\n");
Java Pattern regex search between strings

Java Pattern regex search between strings


By : Pudjo Isnanto
Date : March 29 2020, 07:55 AM
Hope that helps Given the following strings (stringToTest): , You may use this regex with a negative lookahead in between:
code :
G2:(?:(?!G\d+:)\S)*RQ:3,4
String re = "G2:(?:(?!G\\d+:)\\S)*RQ:3,4";
Extract strings from a pattern in java using Matcher and pattern

Extract strings from a pattern in java using Matcher and pattern


By : Nolasco J.
Date : March 29 2020, 07:55 AM
wish help you to fix your issue You can use capturing groups to capture the values. This is the sample code in Java. This works for the specified string but you can tweak and change it accordingly.
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