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KVC without NSObject (NSPredicate)


KVC without NSObject (NSPredicate)

By : user2951262
Date : November 18 2020, 01:01 AM
it fixes the issue Aren't you making this awfully unnecessarily hard for yourself? Why not just use what Swift gives you - filter, hasPrefix, and so on? I don't know what a User actually is, but let's pretend it's something like this:
code :
struct User {
    let username : String = ""
}
let users = [User(username:"Matt Neuburg"), User(username:"Dudley Doright")]
let word = "Matt"
let users2 = users.filter {$0.username.hasPrefix(word)}


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NSPredicate and custom NSObject

NSPredicate and custom NSObject


By : Paweł Kaczmarek
Date : March 29 2020, 07:55 AM
hope this fix your issue If I understood correctly, the format of your predicate is wrong. It should be [NSPredicate predicateWithFormat:@"SUBQUERY(featuresArray, $object, $object.title CONTAINS[c] %@ AND $object.feature = %d).@count > 0", @"some string", FeatureExists]; where you check in your array if any object matches the requirements.
Can't make NSPredicate work on custom NSObject

Can't make NSPredicate work on custom NSObject


By : Krishan Chandak
Date : March 29 2020, 07:55 AM
may help you . Figured it out myself, and the answer is quite frustrating. Instead of defining the predicate this way:
code :
[NSPredicate predicateWithFormat:@"interpretedForm contains[c] '%@'", searchString]
[NSPredicate predicateWithFormat:[NSString stringWithFormat:@"interpretedForm contains[c] '%@'", searchString]]
NSPredicate with Custom NSObject

NSPredicate with Custom NSObject


By : faultymisdirection
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Your object is not a kind of NSString class and therefore is not escaped like a string.
You have to use the description method explicitly or provide predicate with string formatted on your own.
code :
DSIdentifier* dataSource = [DSIdentifier new];
dataSource.identifier = @"identifier";
// the first method
NSPredicate* predicate = [NSPredicate predicateWithFormat:@"property = %@", dataSource.description];
// the second method
NSPredicate* otherPredicate = [NSPredicate predicateWithFormat:[NSString stringWithFormat:@"property = \"%@\"", dataSource]];

NSLog(@"predicate: %@, other predicate: %@", predicate, otherPredicate);
// predicate: property == "identifier", other predicate: property == "identifier"
NSPredicate Value matching between NSArray and NSObject

NSPredicate Value matching between NSArray and NSObject


By : Ramzi Ferchichi
Date : March 29 2020, 07:55 AM
wish of those help I've one NSArray (self.allUsers) with PFUser object inside : , I hope I've understood correctly
code :
  PFUser *pfUser1 = [PFUser new];
  pfUser1.objectId = @"qvFwzbBGky";
  pfUser1.phone    = @"123";

  PFUser *pfUser2 = [PFUser new];
  pfUser2.objectId = @"bar";
  pfUser2.phone    = @"987";

  NSArray *allUsers = @[ pfUser1, pfUser2 ];

  Person *person = [Person new];
  person.phoneNumber = @"123";

  NSArray *anotherArray = @[ person ];


  __block BOOL found;
  __block PFUser *foundedPFUser;
  [anotherArray enumerateObjectsUsingBlock:^(Person *obj, NSUInteger idx, BOOL *stop) {

      NSArray *result = [allUsers filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"%K contains[c] %@", @"phone", obj.phoneNumber]];

      if(result.count){

          found = YES;
          foundedPFUser = result.firstObject;
          *stop = YES;
      }

  }];

  NSLog(@"");
  - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
  {
      __block PFUser *foundedPFUser;
      NSMutableArray *realResult   = [NSMutableArray new];
      [self.tableData enumerateObjectsUsingBlock:^(Person *obj, NSUInteger idx, BOOL *stop) {
          NSArray *result = [self.allUsers filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"%K contains[c] %@", @"phone", obj.number]];
          if(result.count){
              [realResult addObjectsFromArray:result];
          }
      }];

      NSLog(@"%@",realResult);
  }
IOS NSobject deep child filtering with NSpredicate

IOS NSobject deep child filtering with NSpredicate


By : rbi
Date : March 29 2020, 07:55 AM
may help you . , To close this question. The answer comes from Willeke.
code :
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY children.@distinctUnionOfArrays.children.name contains[cd] %@",searchText];
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