How to generate 32 bit UUID in iOS?

How to generate 32 bit UUID in iOS?

By : user2951079
Date : November 18 2020, 01:01 AM
hope this fix your issue A UUID by definition is 128-bit.
A UUID is a 16-octet (128-bit) number.
code :

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Efficient method to generate UUID String in JAVA (UUID.randomUUID().toString() without the dashes)

Efficient method to generate UUID String in JAVA (UUID.randomUUID().toString() without the dashes)

By : CanOfWorms
Date : March 29 2020, 07:55 AM
will help you Ended up writing something of my own based on UUID.java implementation. Note that I'm not generating a UUID, instead just a random 32 bytes hex string in the most efficient way I could think of.
code :
import java.security.SecureRandom;
import java.util.UUID;

public class RandomUtil {
    // Maxim: Copied from UUID implementation :)
    private static volatile SecureRandom numberGenerator = null;
    private static final long MSB = 0x8000000000000000L;

    public static String unique() {
        SecureRandom ng = numberGenerator;
        if (ng == null) {
            numberGenerator = ng = new SecureRandom();

        return Long.toHexString(MSB | ng.nextLong()) + Long.toHexString(MSB | ng.nextLong());
public static void main(String[] args) {

    System.out.println(Long.toHexString(0x8000000000000000L |21));
    System.out.println(Long.toBinaryString(0x8000000000000000L |21));
    System.out.println(Long.toHexString(Long.MAX_VALUE + 1));
uuid-ossp module for PostgreSQL 8.2 to generate UUID

uuid-ossp module for PostgreSQL 8.2 to generate UUID

Date : March 29 2020, 07:55 AM
around this issue You may be confused about the packaging of that plugin for Postgres. Postgres 9.1 introduced a new packaging scheme called Extension. The idea is that the creator of a plugin does more work with regard to packaging so that the user of the plugin might do less work with regard to installation. The Create Extension command (a mis-nomer to my mind) installs a plugin into your Postgres cluster.
Previous to Postgres 9.1, you can install the UUID plugin, but doing so is not quite so simple. You must locate the "uuid-ossp" plugin appropriate to your version of Postgres. The plugin may well have been bundled with your Postgres cluster but not yet installed (activated). Within that plugin package find the SQL script used for installation. You then execute that script in your Postgres cluster.
How to generate UUID with vidibus-uuid?

How to generate UUID with vidibus-uuid?

By : user2038304
Date : March 29 2020, 07:55 AM
wish helps you I use uuidtools
code :
gem 'uuidtools'
# "7b1fdc50-084c-4c20-a0b2-d76c060ed9cd"
class Domain
  include Mongoid::Document

  field :name, type: String
  field :url, type: String
  field :uuid
  validates :uuid, :presence => true

  belongs_to :user

  before_create do
    set_uuid if uuid.blank?


  def set_uuid
    self.uuid = UUIDTools::UUID.random_create.to_s

Generate UUID values by default for each row on column of UUID type in H2 Database Engine

Generate UUID values by default for each row on column of UUID type in H2 Database Engine

By : WVandamme
Date : March 29 2020, 07:55 AM
To fix this issue You can use built-in function RANDOM_UUID():
code :
create table test(id int primary key, data uuid default random_uuid());
insert into test(id) values(1);
select * from test;
Go: convert reflect.Value of type uuid.UUID (satori) back to uuid.UUID again

Go: convert reflect.Value of type uuid.UUID (satori) back to uuid.UUID again

By : Krieglied
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Use a type assertion on the underlying value:
code :
u, ok := reflectedValue.Interface().(uuid.UUID)
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