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Ajax result as an img?


Ajax result as an img?

By : user2951048
Date : November 18 2020, 01:01 AM
around this issue This script is pulling an img link, wich works fine so far, but I have no Idea how to return the link as an img.. Somebody help me! , Try this...
code :
var channel_name = 'justsmoki';
            $.ajax({
                url: 'https://api.twitch.tv/kraken/channels/' + channel_name,
                type: 'GET',
                dataType: 'jsonp',
                contentType: 'application/json',
                mimeType: 'application/vnd.twitchtv.v2+json',
                success: function(json_result) {
                    $('#img').attr("src",json_result.logo);

                }
            });
<img id="img" />


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To continually pull result from the server via Ajax until timeout or getting result

To continually pull result from the server via Ajax until timeout or getting result


By : Adit
Date : March 29 2020, 07:55 AM
this will help I would like to make an Ajax request to the server, which replies a job status and result. If the status is "Error" or "Ok", the client should show the result (containing HTML code) to the user. However, if the status is "Waiting", the client should wait for a few seconds and then automatically send the same Ajax request again. This should continue until it either times out or gets a "Error"/"OK" message. , You can do like
code :
(function refresh(){
   $.ajax({
      url:      '/myfile',
      data:     'data',
      dataType: 'text',
      type:     'POST',
      success:   function(data){
          if(data === 'Waiting')
             setTimeout(refresh, 5000);
          else
             alert(data);
      }
   });
})();
How to get result values of AJAX result using Select2 jquery plugin?

How to get result values of AJAX result using Select2 jquery plugin?


By : user3470980
Date : March 29 2020, 07:55 AM
will be helpful for those in need You need to pass your parameters as 'id' and 'text' rather than product_id and name.
code :
<script type="text/javascript">
$("#product-selector").select2({
    placeholder: "Please select product",
    ajax: {
        url: "index.php?route=catalog/product/getProductBySelection&token=<?php echo $token; ?>",
        dataType: "json",
        data: function(params) {
           return {
               q: params.term, // search term
               page: params.page,
               seller_id: <?php echo $seller_id; ?>
           };
        },
        processResults: function(data, page) {
            var results = [];

            $.each(data, function(index, item) {
                results.push({
                    id: item.product_id,
                    text: item.name
                });
            });

            return {
                results: results
            };

            //console.log(results)

        },
        cache: true
    },
    escapeMarkup: function (markup) { return markup; }, // let our custom formatter work
    minimumInputLength: 1
});
</script>
How to handle result of synchronous ajax call and show or hide div based on result value

How to handle result of synchronous ajax call and show or hide div based on result value


By : wyka
Date : March 29 2020, 07:55 AM
seems to work fine This would be your skeletal structure to implement your on-/offline functionality
code :
function checkConnection() {
    $.ajax({
        url: 'php_scripts/checkconnection.php',
        type: "POST",
        success: function() { $("#openOfflineDIV").hide(); },
        error: function() { $("#openOfflineDIV").show(); }
    }).complete(function () {    // this starts the next connection check in 1 second
        setTimeout(checkConnection, 1000);
    });
});

$(document).ready(checkConnection);   // trigger the inital connection check on DOMReady
RxJS 5 Observable and Angular2 http: Call ajax once, save the result, and subsequent ajax calls use cached result

RxJS 5 Observable and Angular2 http: Call ajax once, save the result, and subsequent ajax calls use cached result


By : Khademul Islam
Date : March 29 2020, 07:55 AM
will help you You can subscribe to the Observable multiple times, so if all you want to do is save the second network request for data shared between two Components, you can cache it in your Service like this:
code :
@Injectable()
export class NameService {

    const nameURL = "http://www.example.com/name";
    private cache: Observable<any>;

    getName() {
        return this.cache || this.cache = this.http.get(nameURL);
    }
}
How to show result in new page when my javascript modify the html and display result of AJAX?

How to show result in new page when my javascript modify the html and display result of AJAX?


By : Damage Acid
Date : March 29 2020, 07:55 AM
wish of those help When i click button the page is modified by javascript but i cannot go back to initial page as modified result is on same page .i want browser to consider modified page by javascript as new page so that i can go back to initial page. , Ok you want to simply go back. I found this code in your JavaScript
code :
 function myDivert(){
     window.location.href="https://tickety-boo-scratch.000webhostapp.com/index1.html";
 }
 function myDivert(){
     window.location.href="https://tickety-boo-scratch.000webhostapp.com";
 }
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