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2 Dimensional Char Array C++


2 Dimensional Char Array C++

By : user2950908
Date : November 17 2020, 11:58 AM
will be helpful for those in need The problem is with board[i][j] = {"||"}; . The string "||" cannot be implicitly converted to a single character.
It's not clear what you are trying to do; each cell of the board is a char, and || is two chars. Two doesn't go into one. Perhaps you meant:
code :
board[i][j] = '|';
int const width = 25;
int const height = 50;
char board[height][width] = {};

for (int h = 0; h < height; h++)
    for (int w = 0; w < width; w++) 


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Allocating memory to a two dimensional char array, error: invalid conversion from ‘void*’ to ‘char**’

Allocating memory to a two dimensional char array, error: invalid conversion from ‘void*’ to ‘char**’


By : myakushka
Date : March 29 2020, 07:55 AM
I hope this helps you . What you wrote is valid C, but invalid C++.
Make sure you use a C compiler, and name your files .c rather than .cpp (GCC will infer language from file extensions in some cases).
Whats wrong with char input for this 2 dimensional char array? why its not taking total of K*K inputs?

Whats wrong with char input for this 2 dimensional char array? why its not taking total of K*K inputs?


By : M Arshad
Date : March 29 2020, 07:55 AM
Does that help I am trying to take 2 dimensional char data from user, but it's not taking input from user properly. Could you highlight the bug in following code? , Problem:
code :
scanf("%c", (*(ch + i) + j) );
int c;
do {
    c = getchar();
}while(c != '\n' && c != EOF);
if (c == EOF) {
    // input stream broken, yell
}
c++ convert 2 dimensional char array const char**

c++ convert 2 dimensional char array const char**


By : Sultana Zahir
Date : March 29 2020, 07:55 AM
Does that help I have an function which takes const ** char as a function parameter. The input I have to call this function is a string which I need to convert to const char** where each row will be a single character of the string. , You can try to use a const_cast the type of your pointer.
code :
int main(int ac, char **av)
{
 const char **const_av = const_cast<const char **>(av);

 return 0;
}
check if a char exists in a char 2 dimensional array

check if a char exists in a char 2 dimensional array


By : Yogen
Date : March 29 2020, 07:55 AM
it should still fix some issue There are three problems in your code.
You need to include in order to use printf.
code :
char matrix[2][2]={
"best","cover",
"orbit","boost"
};
char matrix[4][6]={
"best","cover",
"orbit","boost"
};
#include <stdlib.h> // Not required
#include <string.h> // For strchr()
#include <stdio.h> // For printf()

int main(int argc, char *argv[]) {
    char *pch;
    char matrix[4][6]={
        "best","cover",
        "orbit","boost"
    };
    int i;

    for(i=0;i<4;i++)
    {
        pch=strchr(matrix[i],'b');

        if (pch==NULL)
        {
          printf ("not exists in %s\n",matrix[i]);
        }
        else
        {
          printf("exists in %s\n",matrix[i]);
        }
    }

    return 0;
}
Copy specific range of 2 Dimensional Char[][] Array to char * or std::string

Copy specific range of 2 Dimensional Char[][] Array to char * or std::string


By : Muhammad Asawal
Date : March 29 2020, 07:55 AM
With these it helps To use std::copy you need a pointer to the location of the character, you are passing the character itself here. You also need to initialize outputChar.
code :
char inputChar[5][20] = {"abc","def","ghi01234567890","jkl"};
char * outputChar = new char[20];
auto last = copy(&inputChar[2][0], &inputChar[2][5], outputChar);
*last = '\0';
printf("%s\n", outputChar);
char inputChar[5][20] = {"abc","def","ghi01234567890","jkl"};
string outputChar;
copy(&inputChar[2][0], &inputChar[2][5], back_inserter(outputChar));
printf("%s\n", outputChar.c_str());
string inputChar[5] = {"abc","def","ghi01234567890","jkl"};
int fromChar = 2; // from (inclusive) ^  ^  
int toChar = 5; // to (exclusive)        ^   
string outputChar;
copy(inputChar[2].begin()+fromChar, inputChar[2].begin()+toChar, back_inserter(outputChar));
printf("%s\n", outputChar.c_str());
cout << outputChar << endl;
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