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Take any hash keys and flatten into mixed array


Take any hash keys and flatten into mixed array

By : user2950776
Date : November 17 2020, 11:58 AM
help you fix your problem I have a mixed array like: ["foo", "bar", {test: "stuff"}, "foobar", {just: "examples}]
code :
a = ["foo", "bar", {test: "stuff"}, "foobar", {just: "examples"}]
a.flat_map { |x| x.is_a?(Hash) ? x.values : x }
# => ["foo", "bar", "stuff", "foobar", "examples"]


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flatten ruby hash into array with keys removed

flatten ruby hash into array with keys removed


By : tomekk
Date : March 29 2020, 07:55 AM
will help you Is there a quick way to flatten a hash into an array with the keys removed? , There is a built-in hash method: h.values
Flatten Hash while Iterating over hash's array elements. Ruby

Flatten Hash while Iterating over hash's array elements. Ruby


By : Pham Son
Date : March 29 2020, 07:55 AM
This might help you The input hash can have nests of any combo of Arrays and Hashes (AoA, AoH, HoH, and HoA). Flatting the hash elements to have the proper key and delimiter of _> is no problem. , This is long and complicated, but at least it works:
code :
my_hash = {:x => 333, :y => 13, :z => [1,2,{:zz => [40,50]},[10,20]], :a => {:o => "1", :p => "2"}}


# Create Recursive function to get values:
def advance_hash_flattener(input, parent=[])
  case input
    when Hash then input.flat_map{|key, val|
      advance_hash_flattener(val, parent+[key])}
    when Array then input.flat_map{|x| advance_hash_flattener(x, parent)}
    else [parent.join('_>'), input]
  end
end

#Some small transformations for the last step:
first_step =  advance_hash_flattener(my_hash)
   .each_slice(2)
   .group_by{|x| x.first}
   .map{|x| [x.first, x.last.map(&:last)]}
p first_step #=> [["x", [333]], ["y", [13]], ["z", [1, 2, 10, 20]], ["z_>zz", [40, 50]], ["a_>o", ["1"]], ["a_>p", ["2"]]]

# Create an array of Hashes:
final_array = [Hash.new]
first_step.each do |key,values|
  new = []
  values.each do |val|
    if final_array.first.key?(key)
      final_copy = final_array.map{|x|x.clone}
      final_copy.each{|x| x[key] = val}
      new += final_copy
    else
      final_array.each{|x| x[key] = val}
    end
  end
  final_array += new
end
# result stored in final_array
How to convert an array to a hash with array elements as hash keys and all hash values all set to given value

How to convert an array to a hash with array elements as hash keys and all hash values all set to given value


By : Abel291
Date : March 29 2020, 07:55 AM
To fix this issue Using Ruby 2.1 (with ActiveSupport 3.x, if that helps), I want to convert an array like this: , Another answer:
code :
ary = [ :apples, :bananas, :strawberries ]
Hash[[*ary.each_with_object(20)]]
# => {:apples=>20, :bananas=>20, :strawberries=>20}
ary.each_with_object(20).to_h
# => {:apples=>20, :bananas=>20, :strawberries=>20}
Flatten out a JSON hash map to an array in perl

Flatten out a JSON hash map to an array in perl


By : Jasmin Sanagala
Date : March 29 2020, 07:55 AM
This might help you I am new to data structures and I have a question about it,
code :
use JSON qw( decode_json encode_json from_json to_json );

sub dclone { from_json(to_json($_[0])) }

my $foos_by_comp = decode_json(...);

my @flattened_foos_grouped_by_comp;
for my $comp (keys(%$foos_by_comp)) {
   my @flattened_foos_of_comp;
   my $foo = $foos_by_comp->{$comp};
   for my $search_string (@{ $foo->{searchString} }) {
       my $flattened_foo = dclone($foo);
       $flattened_foo->{ comp         } = $comp;
       $flattened_foo->{ searchString } = $search_string;
       push @flattened_foos_of_comp, $flattened_foo;
   }

   push @flattened_foos_grouped_by_comp, \@flattened_foos_of_comp;
}

print(encode_json(\@flattened_foos_grouped_by_comp));
Flatten a hash and concatenate the keys

Flatten a hash and concatenate the keys


By : Ignacio Carbajal
Date : March 29 2020, 07:55 AM
I wish this helpful for you Adapted from https://stackoverflow.com/a/9648515/311744
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