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Creating classes inside a loop Python


Creating classes inside a loop Python

By : user2950708
Date : November 17 2020, 11:58 AM
should help you out The class statement requires a hard-coded class name. You can use the type function, however, to create such dynamic classes.
code :
names = ['name1', 'name2']
class_dict = {}
for name in names:
    # statements to prepare d
    class_dict[name] = type(name, (object,), d)
d = {}
d['foo'] = 5
def initializer(self, x):
    self.x = x + 6
d['__init__'] = initializer
MyClass = type('MyClass', (object,), d)
class MyClass(object):
    foo = 5
    def __init__(self, x):
        self.x = x + 6


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Scope of classes inside of functions and classes inside of a class in python

Scope of classes inside of functions and classes inside of a class in python


By : Ben Davis
Date : March 29 2020, 07:55 AM
hope this fix your issue The thing to realize is that the class statement just creates a variable whose value is a class. The way the resulting class's scope works is the same the way a variable's scope would work if you just did a normal variable assignment like x = 2.
Any variables you create inside a function are local to that function unless you specify otherwise. So using a class statement inside a function just creates a local variable whose value is a class. It can't be accessed from outside the function.
code :
def foo():
    class A(object):
        pass
def foo():
    A = 2
class A(object):
    class B(object):
        pass
class A(object):
    B = 2
Creating objects inside loop vs. creating one temp object before loop

Creating objects inside loop vs. creating one temp object before loop


By : Victor Seo
Date : March 29 2020, 07:55 AM
wish help you to fix your issue For all realistic, measurable cases, there is absolutely no difference between the two performance wise. In fact, I'm pretty sure (admittedly I don't know for sure) they result in the exact same number of assignments and reference creations. It would be stupid for the JVM to create N number of reference holders. It would simply reuse the one created during the first iteration, simply giving it the reference in the next assignment. Which means only one reference holder is used for both cases (assuming this is true).
Creating a counter inside a Python for loop

Creating a counter inside a Python for loop


By : Mazen Kassab
Date : March 29 2020, 07:55 AM
Any of those help This (creating an extra variable before the for-loop) is not pythonic .
The pythonic way to iterate over items while having an extra counter is using enumerate:
code :
for index, item in enumerate(iterable):
    print(index, item)
lst = ["a", "b", "c"]

for index, item in enumerate(lst):
  print(index, item)
0 a
1 b
2 c
classes and Loop inside python

classes and Loop inside python


By : cris
Date : March 29 2020, 07:55 AM
wish helps you what you doing is returning after it loops and gets the first value and thus it gives back only the first value
Also, you are not incrementing your loop this will result in an infinite loop.
code :
y=[]
while i < x:
    value = A[i]
    y.append(value)
    i+=1
return y
Python: Creating new lists inside while loop

Python: Creating new lists inside while loop


By : N. Tarakanovskiy
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , So in my approach to First-improvement local search I have encountered a point in which I can't seem to move forward. That if-statement and the variables assignment are driving me nuts. When I "debug" it with prints I can't get to see what happens and I need someone to shed light on this matter. , I solved it just adding [:] when assigning the new lists:
code :
best = initial[:]
sol = best[:]
best = sol[:]
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