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How to extend sys.path using files?


How to extend sys.path using files?

By : user2950522
Date : November 17 2020, 11:55 AM
Hope that helps You can create one ore more .pth files in site-packages; their contents will be added to sys.path when present.
From the site module documentation:
code :


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CAKeyframeAnimation with path; can the path be extended to extend the animation?

CAKeyframeAnimation with path; can the path be extended to extend the animation?


By : user2638276
Date : March 29 2020, 07:55 AM
Hope this helps Yes you can - the animation proceeds along the path with appended paths just fine. Now that problem is solved the new problem is how to make animation progress according to touch inputs, not elapsed time.
Find certain files with an extension, get the path, copy files to the path, record path in text file

Find certain files with an extension, get the path, copy files to the path, record path in text file


By : Marlen Jace Roberts
Date : March 29 2020, 07:55 AM
seems to work fine I need to be able to
code :
@echo off
rem in the FOR loop %%~Pa is the directory name and %%~Na the file name
for /R %%a in (*.ac) do (
    if not exist %%~Pa%%~NaMS.cvw (
        copy \fixed\path\%%~NaMS.cvw %%~Pa
        echo %%~Pa>> textfile.txt
    )
)
@echo off
rem in the FOR loop %%~Pa is the directory name and %%~Na the file name
for /R %%a in (*.ac) do (
    for %%b in (cb ia etc mw) do (
        if not exist %%~Pa%%~Na%%b.cvw (
            copy .\jzitfix.cvw %%~Pa%%~Na%%b.cvw > nul
        )
    )
)
In python, how to get the path to all the files in a directory, including files in subdirectories, but excluding path to

In python, how to get the path to all the files in a directory, including files in subdirectories, but excluding path to


By : Carlos Cabrera Carre
Date : March 29 2020, 07:55 AM
this one helps. os.walk(path) returns three tuples parent folder, sub directories and files.
so you can do like this:
code :
for dir, subdir, files in os.walk(path):
    for file in files:
        print os.path.join(dir, file)
How to extend PHP class in mulitple files and mark every extend in namespace?

How to extend PHP class in mulitple files and mark every extend in namespace?


By : user2905784
Date : March 29 2020, 07:55 AM
this one helps. Your main issue as I see it is the lack of the USE statement and the fact that TrigerError is a method and not a class.
To fix these:
code :
namespace Core\MySQLiDrv;

use Core\Errors\Errors;

class MySQLiDrv {
    public $db = null;

    public function __construct($database) {
        $connector = mysqli_connect($database[0], $database[1], $database[2], $database[3]);
        if(!$connector)
        {
            return (new Errors)->TrigerError("1");
        }
    }
}
namespace Core{
    class Engine {
    }
}

namespace Core\Errors{
    class Errors {
        public function TrigerError($e)
        {
            die($e);
        }
    }
}

namespace Core\MySQLiDrv{

    use Core\Errors\Errors;

    class MySQLiDrv {
        public $db = null;

        public function __construct($database) {
            //$connector = mysqli_connect($database[0], $database[1], $database[2], $database[3]);
            //if(!$connector)
            //{
                return (new Errors)->TrigerError("1");
           //}
        }
    }
}

//default global namesapce
namespace {
    use Core\Engine;
    use Core\MySQLiDrv\MySQLiDrv;

    $engine = new Engine();
    $db = new MySQLiDrv(array("localhost", "user", "pass", "db"));

}
1
#Gulp# How to output files to the path which depends on the path of input files?

#Gulp# How to output files to the path which depends on the path of input files?


By : Vwolves Solutions
Date : March 29 2020, 07:55 AM
wish help you to fix your issue This really is something that you can solve by reading any one of a number of gulp articles already out there. Google for gulp tutorial and start reading articles.
By default, the relative source path for an input file is preserved through to the output file in gulp. You don't have to do anything special. If you want something similar to what you've got, you need to use a JS minifier, such as the gulp-uglify plugin, and the gulp-rename plugin.
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