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How is FRP handled in terms of memory?


How is FRP handled in terms of memory?

By : Fabio Carlesso
Date : November 17 2020, 11:55 AM
Hope this helps The fact that this can work for simple cases should not be much of a surprise: we already comfortably use infinite data structures in Haskell thanks to laziness and garbage collection. As long as your final result does not depend on having all your values at once, they can be collected as you go along or not forced in the first place.
This is why this classical Fibonacci example runs in constant¹ space: previous entries in the list are not needed once the next two are calculated, so they are collected as you go along—as long as you do not have any other pointers to the list.
code :
fib n = fibs !! n
  where fibs = 0 : 1 : zipWith (+) fibs (drop 1 fibs)


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iOS - I'm confused how memory is being handled here?

iOS - I'm confused how memory is being handled here?


By : Tatiana
Date : March 29 2020, 07:55 AM
hop of those help?
if [super init] returns nil, nil is returned. so the control returns from method and if (someInitializingFailed) block will never be executed and memory will be leaked as alloc is already executed before calling "initWithFoo"
how does a program runs in memory and the way memory is handled by Operating system

how does a program runs in memory and the way memory is handled by Operating system


By : Luis Alberto Migliet
Date : March 29 2020, 07:55 AM
it should still fix some issue I am not clear with memory management when a process is in execution during run time ,
1) What is the stack which this image is referring to?
How is this memory handled?

How is this memory handled?


By : João Santos
Date : March 29 2020, 07:55 AM
wish helps you When you create an NSArray with objects, it is really a pointer to the array of pointers. What it means is that when you pass the object, the object isn't allocated again, in fact it keeps the reference to the object. It means, if you pass mutable object to the array (like NSMutableString etc.), then you append something to the string, the array will change its value. If you, on the other hand, initialize the object again, with different value, the memory address changes for that object, but array keeps the reference to the old object - it means there are 2 different objects. Better to see it on examples:
Example 1:
code :
NSString *testString = @"Test";
NSArray *testArray = @[testString];

testString = @"Test2";
NSMutableString *testString = [NSMutableString stringWithString:@"Test"];
NSArray *testArray = @[testString];

[testString appendString:@"2"];
NSMutableString *testString = [NSMutableString stringWithString:@"Test"];
NSArray *testArray = @[testString];

testString = [NSMutableString stringWithString:@"Test2"];
what is the difference in defining the 'byte' in terms of computer memory and in terms of C++?

what is the difference in defining the 'byte' in terms of computer memory and in terms of C++?


By : Philip McDonald
Date : March 29 2020, 07:55 AM
With these it helps What the author wants to say about the size of a byte is that, quoting from Wikipedia:
How references are handled in memory

How references are handled in memory


By : Argman
Date : March 29 2020, 07:55 AM
I wish this help you As you declared A::_b as a reference, it will "hold" a reference. Thus the object a does not contain the data of b if you examine a byte-wise.
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