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php variable inside a variable in a while query


php variable inside a variable in a while query

By : user2950395
Date : November 17 2020, 11:55 AM
To fix the issue you can do I have a variable: , Your code looks correct but you have to remove the single quotes
code :
{   echo $data2['$category'] ; } 
{   echo $data2[$category] ; }


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Using a $row variable inside of $_POST variable for a MYSQL query

Using a $row variable inside of $_POST variable for a MYSQL query


By : shehinkp
Date : March 29 2020, 07:55 AM
help you fix your problem Your query's double quotes are a bit awry. You also need to feed mysql_query a resource created by mysql_connect (in the following example, it's represented by $mysql).
code :
mysql_query("INSERT INTO images (image, gallery_name) VALUES('".$target_path."', '". $_POST[$row["name"]]."')", $mysql);
storing a variable's value in another variable and reassigning it to that variable inside a loop in python

storing a variable's value in another variable and reassigning it to that variable inside a loop in python


By : kapr0001
Date : March 29 2020, 07:55 AM
this one helps. It sounds like you are trying to store the original input list in y so that you can restore the value of x partway through your program.
This is not currently working because y = x causes both x and y to refer to the same list. Modifying one will modify the other. Example:
code :
>>> x = [1,2,3]
>>> y = x
>>> y.append(4)
>>> print x
[1, 2, 3, 4]
>>> x = [1,2,3]
>>> y = x[:]
>>> y.append(4)
>>> print x
[1, 2, 3]
x = list(str(raw_input("Please enter a string: ")))

y = x[:]

#later, within the while loop:
    while j<n:
        x = y[:]
How to include a variable inside of a post variable within a query string? -php

How to include a variable inside of a post variable within a query string? -php


By : Andrew
Date : March 29 2020, 07:55 AM
With these it helps If you're happy with having them concatenated straight across, you can simply use:
$_POST['employees'] . $department['dept_id']
code :
$get_depts = mysql_query("select dept_id, dept_name from depts where bus_id = '{$business['bus_id']}'");
while(($department = mysql_fetch_assoc($get_depts)))
{
 //
 // I prefer to do my concat outside of the query!
 //
 $employees = $_POST['employees'] . $department['dept_id'];

 //I assume this query isn't really what you're running.  Pseudo-code, no?
    mysql_query("Update required_fields set employees = '$employees' where dept_id = '{$department['dept_id']}");
}
Writing variable's content to a variable file inside a variable-directory

Writing variable's content to a variable file inside a variable-directory


By : BABLU
Date : March 29 2020, 07:55 AM
around this issue The following command gives No such file or directory error because test directory doesn't exist or Not a directory if it is not a directory.
code :
echo "hello" > test/bla.txt
mkdir -p "$DIR" || { echo "failed to mkdir $DIR"; exit 1;}
echo "$TEXT" > "$DIR/$FILE" || { echo "failed to open $DIR/$FILE for writting"; exit 1;}
Extract and Store javascript variable value inside script written inside executeScript to normal java variable

Extract and Store javascript variable value inside script written inside executeScript to normal java variable


By : Shonai
Date : March 29 2020, 07:55 AM
I hope this helps you . I found the solution myself. I used java and succeeded. I imported javax.swing.JOptionPane library and created object of JOptionPane class. Then used showInput dialog method and I stored the value I put in that dialog in a variable. It worked.
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