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MYSQL fill group by "gaps"


MYSQL fill group by "gaps"

By : Greg Womack
Date : November 17 2020, 11:52 AM
I hope this helps you . Without knowing how you create your group by result table, what you're looking for in an outer join, perhaps with coalesce. Something like this:
code :
select distinct a.date, coalesce(b.quantity,0) quantity
from aux a 
    left join yourgroupbyresults b on a.date = b.date
select a.date, count(b.date_sent)
from aux a
    left join orders b on a.date = date_format(b.date_sent, '%Y-%m-%d')
group by a.date


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MySQL - Join 2 tables with "repeating values" to fill in gaps in time series

MySQL - Join 2 tables with "repeating values" to fill in gaps in time series


By : sopotos
Date : March 29 2020, 07:55 AM
this will help One way to get the result is to use a correlated subquery:
UPDATED
code :
SELECT t1.JDAY
     , (SELECT t2.WSC FROM Table2 t2 
         WHERE t2.JDAY < t1.JDAY
         ORDER BY t2.JDAY DESC LIMIT 1
       ) AS WSC
  FROM Table1 t1
 ORDER BY t1.JDAY 
SELECT t.JDAY
     , s.WSC
  FROM ( SELECT t1.JDAY
              , MAX(t2.JDAY) AS max_t2_jday
           FROM Table1 t1
           LEFT
           JOIN Table2 t2
             ON t2.JDAY < t1.JDAY
          GROUP BY t1.JDAY
          ORDER BY t1.JDAY
       ) t
  LEFT
  JOIN Table2 s
    ON s.JDAY = t.max_t2_jday
Force facet_wrap to fill bottom row (and leave any "gaps" in the top row)

Force facet_wrap to fill bottom row (and leave any "gaps" in the top row)


By : Anil
Date : March 29 2020, 07:55 AM
hope this fix your issue I'd like to force facet_wrap to fill from the top-left, but in such a way as to always fully fill the bottom row. (That is, from the top-left plus whatever horizontal offset is required to fully fill the bottom row.) , Would this fix suffice?
code :
library(ggplot2)
n <- 1000
df <- data.frame(x = runif(n), y=rnorm(n), label = sample(letters[1:7], 
                 size = n, replace = TRUE), stringsAsFactors=TRUE)
# following @Didzis' suggestion (with some minor changes)
df$label.new <- factor(df$label, levels=sort(c(""," ",levels(df$label))))
p <- ggplot(df, aes(x=x, y=y)) + geom_point() + 
         facet_wrap(~ label.new, ncol=3,drop=FALSE)
g = ggplotGrob(p)
## remove empty panels
g$grobs[names(g$grobs) %in% c("panel1", "panel2", "strip_t.1", "strip_t.2")] = NULL
## remove them from the layout
g$layout = g$layout[!(g$layout$name %in% c("panel-1", "panel-2", 
                                                "strip_t-1", "strip_t-2")),]
## move axis closer to panel
g$layout[g$layout$name == "axis_l-1", c("l", "r")] = c(9,9)
grid.newpage()
grid.draw(g)
Excel/Google sheets: formula to "fill in the gaps"

Excel/Google sheets: formula to "fill in the gaps"


By : Chris Puckett
Date : March 29 2020, 07:55 AM
With these it helps Select A1:A20 (e.g. the cell with 0.2151452046 to the cell with 0.235) and choose Home ► Editing ► Fill ► Series Enter↵. Also accessed through Alt+H,FI,S,Enter↵.
How to improve MySQL "fill the gaps" query

How to improve MySQL "fill the gaps" query


By : Jakob Rydberg
Date : March 29 2020, 07:55 AM
it should still fix some issue I have a solution for a while now: get rid of dependent subqueries. I had to think from different angles in mutliple places and here is the result:
code :
SELECT
  cd.date_id,
  x.currency,
  x.rate
FROM
  imp_exchangerate x INNER JOIN 
  (SELECT
    d.date_id,
    max(rate_date) as rate_date,
    currency
  FROM
    d_date d INNER JOIN
    imp_exchangerate ON rate_date <= d.full_date
  WHERE
    d.full_date <= curdate()
  GROUP BY
    d.date_id,
    currency) cd ON x.rate_date = cd.rate_date and x.currency = cd.currency
MYSQL: Left JOIN from two SELECT to "fill gaps" in dates

MYSQL: Left JOIN from two SELECT to "fill gaps" in dates


By : alittlesheep
Date : March 29 2020, 07:55 AM
seems to work fine I take a look on your question and i came up with this solution. Here is how your query could look like:
code :
SELECT t1.NUM_WEEK, t1.`YEAR`, t1.date_start, t1.id_account, t2.total
FROM (SELECT c.NUM_WEEK, c.`YEAR`, c.date_start, a.id_account
      FROM (SELECT WEEK(day_date,1) AS NUM_WEEK,
                   YEAR(day_date) AS `YEAR`,
                   STR_TO_DATE(CONCAT(YEAR(day_date),WEEK(day_date,1),' Monday'), '%X%V %W') AS date_start,
                   (SELECT GROUP_CONCAT(id_account) FROM account WHERE id_customer=12) AS accounts_id 
             FROM calendar
             GROUP BY NUM_WEEK) c
       INNER JOIN account a
       ON FIND_IN_SET(a.id_account, c.accounts_id)
       ORDER BY a.id_account, c.NUM_WEEK) t1
LEFT JOIN
     (SELECT WEEK(t.date_transaction,1) AS NUM_WEEK,
             YEAR(t.date_transaction) AS `YEAR`,
             STR_TO_DATE(CONCAT(YEAR(t.date_transaction),WEEK(t.date_transaction,1),' Monday'), '%X%V %W') AS date_start,
             t.id_account, SUM(t.amount) AS total 
      FROM `transaction` t
      INNER JOIN account a 
      ON a.id_account = t.id_account
      WHERE t.amount > 0 AND 
            t.id_account IN (SELECT id_account FROM account WHERE id_customer = 12)
      GROUP BY id_account, WEEK(date_transaction,1)) t2
 ON t1.NUM_WEEK = t2.NUM_WEEK AND t1.YEAR = t2.YEAR AND t1.id_account = t2.id_account;
SELECT WEEK(day_date,1) AS NUM_WEEK,
       YEAR(day_date) AS `YEAR`,
       STR_TO_DATE(CONCAT(YEAR(day_date),WEEK(day_date,1),' Monday'), '%X%V %W') AS date_start,
       (SELECT GROUP_CONCAT(id_account) FROM account WHERE id_customer=12) AS accounts_id 
FROM calendar
GROUP BY NUM_WEEK
(SELECT GROUP_CONCAT(id_account) FROM account WHERE id_customer=12) AS accounts_id
SELECT c.NUM_WEEK, c.`YEAR`, c.date_start, a.id_account
FROM (SELECT WEEK(day_date,1) AS NUM_WEEK,
             YEAR(day_date) AS `YEAR`,
             STR_TO_DATE(CONCAT(YEAR(day_date),WEEK(day_date,1),' Monday'), '%X%V %W') AS date_start,
             (SELECT GROUP_CONCAT(id_account) FROM account WHERE id_customer=12) AS accounts_id 
       FROM calendar
       GROUP BY NUM_WEEK) c
INNER JOIN account a
ON FIND_IN_SET(a.id_account, c.accounts_id)
ORDER BY a.id_account, c.NUM_WEEK
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