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Return only array data without return the function itself using Array.prototype


Return only array data without return the function itself using Array.prototype

By : user2950258
Date : November 17 2020, 11:52 AM
I wish this help you You're using for...in, which iterates over the enumerable properties of the object, including the function you've added to the prototype. That is expressly not how you're meant to iterate over arrays.
If you want to iterate over an array, you should use a simple for loop, and count from 0 to length - 1...
code :
for (var i = 0; i < this.length; ++i) {
  console.log(this[i]);
}
this.forEach(function (i) {
  console.log(i);
});


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How can I return the array object from Array's prototype function?

How can I return the array object from Array's prototype function?


By : user3797792
Date : March 29 2020, 07:55 AM
This might help you Quoting MDN on Array.prototype.push,
code :
Array.prototype.toTwenty = function () {
    return [4, 6];
};

Array.prototype.search = function (lb) {
    if (lb > 2) {
        this.push(4000);            // Don't return here
    }
    return this;                    // Return the array object itself.
};

console.log([].toTwenty().search(6));
// [ 4, 6, 4000 ]
How to return accumulated returned Promise values as array to .then() following Array.prototype.reduce()?

How to return accumulated returned Promise values as array to .then() following Array.prototype.reduce()?


By : Robert
Date : March 29 2020, 07:55 AM
help you fix your problem There are multiple possible strategies depending upon the specifics of what you're trying to do: Here's one option:
code :
someArray.reduce(function(p, item) {
  return p.then(function(array) {
    return someFunction(item).then(function(val) {
        array.push(val);
        return array;
    });
  });
}, $.Deferred().resolve([])).then(function(array) {
  // all done here
  // accumulated results in array
}, function(err) {
  // err is the error from the rejected promise that stopped the chain of execution
});
var someArray = [1,2,3,4];

Promise.mapSeries(someArray, function(item) {
    return someFunction(item);
}).then(function(results) {
    log(results);
});
Array.Prototype ForEach Wait For Callback Function To Return In Recursive Function

Array.Prototype ForEach Wait For Callback Function To Return In Recursive Function


By : Matt Burchett
Date : March 29 2020, 07:55 AM
I wish did fix the issue. You can promisify your method and then await.
code :
 const Promise  = require('bluebird');
    let encode = Promise.promisify(base64.encode)

    const iterate = async (obj) =>
    {
        Object.keys(obj).forEach((key) =>
        {
            if(key === 'filename')
            {
                        obj[key] = await encode(`https://example.com/${obj[key]}`, { string: true });
            }
            if(typeof obj[key] === 'object' && obj[key] !== null)
            {
                iterate(obj[key]);
            }
        });
    };
JavaScript: Return Rating Value from Array Using Internal Prototype Method within Factory Function

JavaScript: Return Rating Value from Array Using Internal Prototype Method within Factory Function


By : user2929538
Date : March 29 2020, 07:55 AM
it fixes the issue I am trying to create an object from a factory function. This object contains an internal prototype which consists of different methods. , Just use reduce to sum all the values, then divide by the length.
code :
getStars() {
  let allStars = this.ratings.reduce((a, { length: c }) => a + c, 0);
  let avg = allStars / this.ratings.length;
  return avg;
}
getStars() {
  return this.ratings.reduce((a, { length: c }) => a + c, 0) / this.ratings.length;
}
function prototype return 2D array in C

function prototype return 2D array in C


By : ansj
Date : March 29 2020, 07:55 AM
To fix this issue I am not very good at C and I am really confused about double array. Below is an outline of a code I have a question about. Main function calls CreateRandConn function and passes it a 2D array filled with 0 as an argument. CreateRandConn function takes a 2D array as a parameter, changes some of the value in 2DArray from 0 to 1 and returns the changed 2DArray back to main. I want to indicate in the function prototype the return type of CreateRandConn function is a 2D array. How do I indicate that? I don't really understand the syntax. Is what I wrote wrong? Is the way I am passing the 2DArray as a parameter in the function header incorrect? If so, how I do write it? I still get confused about the relationship between pointers and double arrays. Can someone explain it with the below code outline? Hopefully someone knows what my question is... ,
I don't really understand the syntax.
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