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Call forwarding from one function to another


Call forwarding from one function to another

By : Ricardo Lazaro Olive
Date : November 17 2020, 11:52 AM
Hope that helps Yes, it's fine to call it this way if this is never used within g's body.
Note that one often has no alternatives to apply when passing arguments from outer function (a facade) to a specific implementation, when the former is a variadic function - both call and direct invokation require list of arguments.
code :


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C++11 variadic template function call forwarding

C++11 variadic template function call forwarding


By : DonaldTrumpsHair
Date : March 29 2020, 07:55 AM
With these it helps Using the indices trick, this is rather easy:
code :
template<unsigned...> struct indices{};

template<unsigned N, unsigned... Is>
struct indices_gen : indices_gen<N-1, N-1, Is...>{};

template<unsigned... Is>
struct indices_gen<0, Is...> : indices<Is...>{};

// assuming the parameters were actually like this
template<typename Return, typename... Args, unsigned... Is>
Variant* wrapCFunction(Return (*cfunc)(Args...), int argc, Variant** argv, indices<Is...>) {
    return cfunc(convertFromVariant<Args>(argv[Is])...);
}

template<typename Return, typename... Args>
Variant* wrapCFunction(Return (*cfunc)(Args...), int argc, Variant** argv) {
    if (argc != sizeof...(Args))
        throw std::runtime_error("bad argument count");
    return wrapCFunction(cfunc, argc, argv, indices_gen<sizeof...(Args)>());
}
Why does Twilio call forwarding operate differently than carrier call forwarding?

Why does Twilio call forwarding operate differently than carrier call forwarding?


By : user2807647
Date : March 29 2020, 07:55 AM
I wish this helpful for you Twilio Programmable Voice uses Twilio Markup Language (TwiML) to control the call flow. If you call your Twilio number and want to forward that call to an end-point off Twilio, Twilio still remains in the signaling and media path, which allows you to remain in control of the call, which is the key part of why that call path is the way it is.
There is no way to remove Twilio from this call flow, as Programmable Voice depends on Twilio remaining in the call path.
How to implement Call Recording to work with Twilio Call Forwarding Function

How to implement Call Recording to work with Twilio Call Forwarding Function


By : Jimut1327
Date : March 29 2020, 07:55 AM
I wish this helpful for you I have setup a twilio number and call forwarding to work with my Google Analytics. I was using Google Dynamics Forwarding numbers but they where not connecting to my VoIP provider. , You can use the Record attribute of the Dial verb to record the call.
code :
if (allowedThrough) {
    twiml.dial(
       {
       action :encodeURI(actionUrl),
       method:'GET',
       record: 'record-from-ringing'
       },phoneNumber
    );
}
How to get a forwarding function to call a base template function that is declared after the forwarding function

How to get a forwarding function to call a base template function that is declared after the forwarding function


By : user3554053
Date : March 29 2020, 07:55 AM
Any of those help The name test in fwd is a dependent name. It will be resolved into two steps:
Non-ADL lookup examines function declarations ... that are visible from the template definition context. ADL examines function declarations ... that are visible from either the template definition context or the template instantiation context.
code :
namespace my_namespace
{
    struct Tag {};

    template<typename T, std::enable_if_t<std::is_scalar<T>::value, int> = 0>
    void test(const T& t, Tag = Tag{}) {
        std::cout << "Scalar" << std::endl;
    }

    template<typename T> 
    void fwd(T&& t) {
        test(std::forward<T>(t), Tag{});
    }

    template<typename T>
    void test(const std::vector<std::vector<T>>& t, Tag = Tag{}) {
        std::cout << "vector vector of T" << std::endl;
    }
}

int main() {
    my_namespace::test(std::vector<std::vector<int>>()); // OK
    my_namespace::fwd(std::vector<std::vector<int>>());  // OK, too
}
template<class T>
struct Test {
    static void op(const T& t) {
        std::cout << "Scalar" << std::endl;
    }
};

template<typename T>
void fwd(T&& t) {
    Test<std::decay_t<T>>::op(std::forward<T>(t));
}

template<class T>
struct Test<std::vector<std::vector<T>>> {
    static void op(const std::vector<std::vector<T>>& t) {
        std::cout << "vector vector of T" << std::endl;
    }
};

int main() {
    fwd(1);
    fwd(std::vector<std::vector<int>>());
}
Perfect forwarding to function pointer call

Perfect forwarding to function pointer call


By : IamAuser123
Date : March 29 2020, 07:55 AM
wish helps you I'm trying to compile simple templetized wrapper in Visual Studio 2015 , You have to split args to allow correct deduction:
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