C RUBY-ON-RAILS MYSQL ASP.NET DEVELOPMENT RUBY .NET LINUX SQL-SERVER REGEX WINDOWS ALGORITHM ECLIPSE VISUAL-STUDIO STRING SVN PERFORMANCE APACHE-FLEX UNIT-TESTING SECURITY LINQ UNIX MATH EMAIL OOP LANGUAGE-AGNOSTIC VB6 MSBUILD

# Index of element in sorted()

By : MOHAN
Date : November 17 2020, 11:52 AM
this will help You could pass into sorted not a collection of elements, but the indices of the elements:
code :
``````let a = ["hello","i","must","be","going"]
let idxs = sorted(indices(a)) { a[\$0] < a[\$1] }
// produces [3, 4, 0, 1, 2]
``````
``````let pairs = sorted(Zip2(indices(a),a)) {
\$0.1 < \$1.1
}
``````
``````let values = PermutationGenerator(elements: a, indices: idxs)
println(" ".join(values)) // prints "be going hello i must"
``````

Share :

## How to find the index of an element in sorted set?

By : user3050158
Date : March 29 2020, 07:55 AM
like below fixes the issue With a simple BST where the order of insertion of elements in random, you have way to determine how many elements exactly are smaller than a given element without walking the tree.
If you had a balanced tree, such as a red-black tree, then you could at least put a lower and upper bound on the index due to the bounds on the height of the tree. If the order of insertion of elements to a BST is non-random then again, you could say something about the tree height without walking it and give some estimate of the approximate index.

## C++ - index of element in sorted std::vector

By : Data Track
Date : March 29 2020, 07:55 AM
This might help you You want to use the lower_bound() function. It's a little bit funky to make it generally useful, but serves the purpose you want.

## FInd index of an element in sorted array, if not found, print index where it should be inserted

By : huangma
Date : March 29 2020, 07:55 AM
To fix the issue you can do Problem with your logic in else statement of last loop.
Correct Code-
code :
``````#include<stdio.h>
int main(){
int n,t,i,k=0,l=0;
int arr[50];
scanf("%d",&n);
for(i=0;i<n;i++){
scanf("%d",&arr[i]);
}
scanf("%d",&t);
// Array size should be less than 50
if(n>50||n<=0){
printf("Array size exceeded");
return 0;
}
//Check array is sorted and has no duplicates
for(i=0;i<n-1;i++){
if(arr[i] == arr[i+1])
k++;
if(arr[i] > arr[i+1])
l++;
}
if(k!=0){
printf("No duplicates allowed");
return 0;
}
if(l!=0){
printf("Array must be sorted");
return 0;
}
//Find element index or print where it should be inserted
for(i=0;i<n;i++){
if(arr[i] == t){
printf("%d",i);
return 0;
}
if(arr[i] > t){
printf("%d",i);
return 0;
}
else{
printf("%d",i+1);
return 0;
}
}
}
``````

## Finding Index of element in sorted array

By : user2489339
Date : March 29 2020, 07:55 AM
should help you out Below is a code that let the user insert a number to search.
The code return the index of the number if it can be found in the sorted list.
code :
``````NUMBERS = [4, 6, 2, 12, 56, 34, 90]

sorted_numbers = sorted(NUMBERS)

number_to_search = input("Search for Element:")

try:
idx = sorted_numbers.index(number_to_search)
print('The index of {} is {}.'.format(number_to_search, idx))
except ValueError:
print('Cant find the number {}.'.format(number_to_search))
``````

## How can I get index of sorted list where element changes?

By : Sneha
Date : March 29 2020, 07:55 AM
wish of those help You could iterate the array and check the predecessor. If equal, increment the last count, otherwise add the index and a count of one.
code :
``````var array = [1, 1, 1, 3, 3, 5, 5, 5, 5, 5, 6, 6],
{ indices, counts } = array.reduce((r, v, i, a) => {
if (a[i - 1] === v) {
r.counts[r.counts.length - 1]++;
} else {
r.indices.push(i);
r.counts.push(1);
}
return r;
}, { indices: [], counts: [] });

console.log(...indices);
console.log(...counts);``````