Python - IndexError

Python - IndexError

By : Len Kun
Date : November 17 2020, 11:52 AM
I wish this help you As the others have noted, your list indices begin with zero, making 19 the last element.
Another related thing you might want to consider doing is instead of getting a range from 0 to 19, do this instead:
code :
for n in range(len(mylist)):

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Another IndexError with python

Another IndexError with python

By : JeKin
Date : March 29 2020, 07:55 AM
wish of those help You've got several bugs. For example, you're checking the value y against 0 even though it is always in the range 1-4, probably unintended behavior. Furthermore, you never actually call a function that gets you a character, and you never create a string. Thus it's not clear what you're trying to do.
Here's how I'd rewrite things based on my guess of what you want to do.
code :
import random, itertools

voks = frozenset('aeiouy')
abc = 'abcdefghijklmnopqrstuvwxyz'

def r_gen():
    last=None #both classes ok
    while 1:
        new = random.choice(abc)
        if (new in voks) != last:
            yield new
            last = (new in voks)

def name(): #Final product
    length = random.randrange(4, 8)
    return ''.join(itertools.islice(r_gen(), length))
Python:IndexError: list index out of range in python

Python:IndexError: list index out of range in python

By : Shah
Date : March 29 2020, 07:55 AM
seems to work fine I am not recommending that you do this (see below for a dictionary based solution), however, you can use the exec statement to assign None to the variables:
code :
dList = ['market_a', 'market_b', 'market_c', 'market_d', 'market_e', 'market_f', 'market_g']

for var in dList:
    exec '{} = None'.format(var)
for var in dList:
    exec 'del {}'.format(var)
    # exec '{} = None'.format(var)
markets = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5, 'f': 6, 'g': 7}

# to access a "variable"
>>> markets['a']

# to modify a "variable"
>>> markets['a'] += 100
>>> markets['a']
del markets
markets = {}
# to delete a specific "variable"
del markets['a']
IndexError - Using Python 3.4.3

IndexError - Using Python 3.4.3

By : neil armstrong
Date : March 29 2020, 07:55 AM
should help you out Checking the next element against the length of the list doesn't help; you need to check the next index ... ... and do this before you access the elements. You need to to keep it from going out of bounds. A list of length k has indices 0:(k-1), but your test allows i+1 to run to the value of k, which causes your access to be out of bounds.
New check: note the change from <= to <, and reversing the order.
code :
if i + 1 < len(n) and n[i] == n[i+1]:
if len(n) >= 2:

    for i in range(len(n)-1):
        if n[i] == n[i + 1]:
            return True           # Exit early if you find a pair

return False    
Python : IndexError

Python : IndexError

By : Matthew Nguyen
Date : March 29 2020, 07:55 AM
This might help you I'm trying to code a basic bubble sort algorithm in Python, here's the code: , You need to update the below line
code :
strength[x].append(int(input("Enter strength of vaccine {} :".format(x))))
midicl[x].append(int(input(("Enter midichlorian count of patient {} :".format(x)))))
strength.append(int(input("Enter strength of vaccine {} :".format(x))))
midicl.append(int(input(("Enter midichlorian count of patient {} :".format(x)))))
How to fix IndexError in Python

How to fix IndexError in Python

By : user3389104
Date : March 29 2020, 07:55 AM
help you fix your problem As a general rule it is a very bad practice to modify the thing you are iterating, especially if you are deleting its contents (there are far too many examples in SO on this issue to list).
Always, you either iterate in a copy of the list to modify the original, or iterate the original creating/modifying a copy:
code :
left_days_1 = list(left_days)
for i in range(len(left_days_1)):
    largest = left_days[0]
    count = 1
    del left_days[0]

        count+= 1
        del left_days[i]
        if i == len(left_days)-1:
        i = 0

    elif left_days_1[i]>largest:
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