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Parse.com and closures


Parse.com and closures

By : Shazi Aziz
Date : November 17 2020, 04:28 AM
it fixes the issue I will give you an example to prevent my bad english cause misleading.
The following rewrite function makeAuthenticatedRequest() in callback deferred antipattern and promise fashion.
code :
function makeAuthenticatedRequest(){
    // generate the appropriate auth Header;
    var digestAuthHeader = generateDigestAuthHeader();
    var promise = new Parse.promise();
    Parse.Cloud.httpRequest({
        method: 'GET',
        url: url,
        headers: {
            "Authorization" : digestAuthHeader
        },
        success: function(httpResponse) {
            // all went well, let's increase the nonceCount, for future calls
            authData["nc"] += 1;
            // create the final object to return in a promise
            result = httpResponse.data;

            console.log(result) // returns something not null!!!

            // return a Promise that can be handled by any function
            promise.resolve({'authData': authData, 'result': result});
        },
        error: function(error) {
            console.error('Request failed with response code ' + error.status);
            // it could be promise.resolve (success) or promise.reject (error)
            promise.reject(error);
        }
    });
    return promise;
}
function makeAuthenticatedRequest(){
    // generate the appropriate auth Header;
    var digestAuthHeader = generateDigestAuthHeader();

    return Parse.Cloud.httpRequest({
            method: 'GET',
            url: url,
            headers: {
                "Authorization" : digestAuthHeader
            }
        }).then(function(httpResponse) {
            // all went well, let's increase the nonceCount, for future calls
            authData["nc"] += 1;
            // create the final object to return in a promise
            result = httpResponse.data;

            console.log(result) // returns something not null!!!

            // return a Promise that can be handled by any function
            return {'authData': authData, 'result': result};
        }, function(error) {
            console.error('Request failed with response code ' + error.status);
            return Parse.Promise.error(error);
        });
}


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What limitations have closures in Python compared to language X closures?

What limitations have closures in Python compared to language X closures?


By : Beth S
Date : March 29 2020, 07:55 AM
With these it helps The most important limitation, currently, is that you cannot assign to an outer-scope variable. In other words, closures are read-only:
code :
>>> def outer(x): 
...     def inner_reads():
...         # Will return outer's 'x'.
...         return x
...     def inner_writes(y):
...         # Will assign to a local 'x', not the outer 'x'
...         x = y
...     def inner_error(y):
...         # Will produce an error: 'x' is local because of the assignment,
...         # but we use it before it is assigned to.
...         tmp = x
...         x = y
...         return tmp
...     return inner_reads, inner_writes, inner_error
... 
>>> inner_reads, inner_writes, inner_error = outer(5)
>>> inner_reads()
5
>>> inner_writes(10)
>>> inner_reads()
5
>>> inner_error(10)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 11, in inner_error
UnboundLocalError: local variable 'x' referenced before assignment
>>> def outer(x):
...     x = [x]
...     def inner_reads():
...         # Will return outer's x's first (and only) element.
...         return x[0]
...     def inner_writes(y):
...         # Will look up outer's x, then mutate it.      
...         x[0] = y
...     def inner_error(y):
...         # Will now work, because 'x' is not assigned to, just referenced.
...         tmp = x[0]
...         x[0] = y
...         return tmp
...     return inner_reads, inner_writes, inner_error
... 
>>> inner_reads, inner_writes, inner_error = outer(5)
>>> inner_reads()
5
>>> inner_writes(10)
>>> inner_reads()
10
>>> inner_error(15)
10
>>> inner_reads()
15
PHP parse error while creating closures on a Class static variable

PHP parse error while creating closures on a Class static variable


By : Lucas Stacy
Date : March 29 2020, 07:55 AM
help you fix your problem The reason why this is not working is that in PHP it is not allowed to assign a closure directly to a (static) class variable initializer.
So for your code to work, you have to use this workaround:
code :
<?php

class ABC {
    public static $funcs;
}

ABC::$funcs  = array(
        'world' => function() {
            echo "Hello,";
            echo "World!\n";
        },
        'universe' => function() {
            echo "Hello,";
            echo "Universe!\n";
        },
);

$func = ABC::$funcs['world'];
$func();
Swift parse framework and closures

Swift parse framework and closures


By : user3756297
Date : March 29 2020, 07:55 AM
Does that help This error that you are getting is, as you've guessed already that you need to hvae gameScore object as an optional.
Swift - Parse.com - Why this closures are wrong?

Swift - Parse.com - Why this closures are wrong?


By : Aston Bildren
Date : March 29 2020, 07:55 AM
With these it helps I guess you should replace PFUser! and NSError! with PFUser? and NSError?
And also, have a closer look at this closure :
code :
sweeter.signUpInBackgroundWithBlock({
                    (success: Bool(), error: NSError()) -> Void in
                    if error == nil {
                        println("sign up successful")
                    } else {
                        let errorString = error.userInfo["error"] as String
                        println(errorString)
                    }
                })
 if (PFUser) {
let errorString = error.userInfo["error"] as String
Unable to parse json using alamofire using closures

Unable to parse json using alamofire using closures


By : Elisha
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I recommend you that use SwiftJson (https://cocoapods.org/pods/SwiftyJSON)
if you need to validate that something exist you can use .exist() (Return a boolean)
code :
func test() {
        let json: JSON = [   "data":[
            "level1":[
                "level2":[
                    "parameter1":"000000",
                    "parameter2":"00/00/00 00:00:00",
                    "parameter3":"00.0"
                ]
            ]
            ]
            ]
            print(json) //Create a breakpoint here
    }
if json["data"]["level1"]["level2"]["parameter1"].exists(){

        }
if json["data"]["level1"]["level2"]["parameter1"].exists(){

            let parameter1 = json["data"]["level1"]["level2"]["parameter1"]
            print(parameter1)
        }
func test() {
        let json: JSON = [   "data":[
            "level1":[
                "level2":[
                    "parameter1":"000000",
                    "parameter2":"00/00/00 00:00:00",
                    "parameter3":"00.0"
                ]
            ]
            ]
            ]
        if json["data"]["level1"]["level2"]["parameter1"].exists(){

            let parameter1 = json["data"]["level1"]["level2"]["parameter1"]
            print(parameter1)
        }
            print(json["parameter1"])
    }
000000
{
  "data" : {
    "level1" : {
      "level2" : {
        "parameter1" : "000000",
        "parameter3" : "00.0",
        "parameter2" : "00\/00\/00 00:00:00"
      }
    }
  }
}
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