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Jquery Tab Content


Jquery Tab Content

By : user2949828
Date : November 17 2020, 04:28 AM
wish of those help Apologies if the answer is glaringly obvious. , add # to href to be
code :
<ul class="tabs">
    <li><a href="#tab1">Tab 1</a></li>
    <li><a href="#tab2">Tab 2</a></li>
    <li><a href="#tab3">Tab 3</a></li>
    <li><a href="#tab4">Tab 4</a></li>
 </ul>


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jQuery to check LI's content - add specific class based on content - trouble with jQuery's $(this)

jQuery to check LI's content - add specific class based on content - trouble with jQuery's $(this)


By : Sasindu JAyashma
Date : March 29 2020, 07:55 AM
help you fix your problem You don't need to loop over the li elements. Working with the sample markup you posted, here's how you can add a class to the About li element.
code :
$('#nav li:contains(About)').addClass('about')
$('#nav li:contains(Contact)').addClass('contact')
$('#nav li:contains(News)').addClass('news')
Remove old content, load in new content, animate new content with JQuery

Remove old content, load in new content, animate new content with JQuery


By : Joker86
Date : March 29 2020, 07:55 AM
I wish did fix the issue. What you're asking it to perform everything after your load() only when it loads something ...
load() is async and you can see the full signature of the method in jQuery website, where it says that you can append a function that will fire when the load as completed.
code :
var clickedAnchors = [];

$(document).ready(function() {

    $('#nav li a').click(function() {

        var toLoad = $(this).attr('href')+' #content';        
        var oldHeight = $('#content').css("height");        
        var viewportHeight = $(window).height();

        $('#content').animate({
            top: "-" + oldHeight
        }, 'slow', function() {

          $('#content').hide();        
          $('#content').load(toLoad, function() {


            $('#content').animate({
               top: viewportHeight + "px"
            });

            $('#content').show();        
            $('#content').animate({
                top: "0px"
            }, 'slow');

          }); // close load

        }); // close animate

        return false;

    }); // close selector
}); // close document.ready
var clickedAnchors = [];

$(document).ready(function() {

    $('#nav li a').click(function() {

      var currentId = $(this).attr('id');

      if($.inArray(currentId, clickedAnchors) < 0) {
        // this anchor was not yet clicked

        var toLoad = $(this).attr('href')+' #content',        
            oldHeight = $('#content').css("height"),        
            viewportHeight = $(window).height();

        $('#content').animate({ top: "-" + oldHeight }, 'slow', function() {

            // after animated is completed
            $('#content')
                .hide()
                .load(toLoad, function() {    

                    $(this).animate( { top: viewportHeight + "px" }, function() {

                        // after animation has completed
                        $(this)
                           .show()
                           .animate({ top: "0px" }, 'slow');

                    });
                });
        });

        // remove this anchor from being clicked again,
        // so let's add it's id into the array
        clickedAnchors.push(currentId);
      }

      return false;

    });
});
How do I programmatically upload pics and content on Google Content Delivery Network using jquery

How do I programmatically upload pics and content on Google Content Delivery Network using jquery


By : phptrend
Date : March 29 2020, 07:55 AM
Hope this helps I have written full tutorial on this topic here, http://verysimplescripts.blogspot.com/
jQuery .post() content reverts back to original content with subsequent jQuery calls

jQuery .post() content reverts back to original content with subsequent jQuery calls


By : Todd Rivers
Date : March 29 2020, 07:55 AM
may help you . Your highlight function is never called, because it's not connected with the dynamically created button. Because of that default action of submit button is called - the form is submitted and the page is refreshing because there is no action URL defined. And that's why you see the page as it was before the $.post call.
To fix this you should change this line
code :
$("#submitBtn").on("click", highlight);
$("body").on("click", "#submitBtn", highlight);
Using Selenium, how do I read content in JQuery-based page when JQuery UI seems to make content of web elements 'un read

Using Selenium, how do I read content in JQuery-based page when JQuery UI seems to make content of web elements 'un read


By : Rouvem
Date : March 29 2020, 07:55 AM
This might help you In order to get text inside a textbox, you have to get attribute "value". See Java code below:
code :
WebElement txtbox = driver.findElement(By.xpath("//div[@class='stepContainer']//td[@class='DataTD']//input[@id='myElementId']"));
string text = txtbox.getAttribute("value");
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