logo
down
shadow

Most Common letter in a string


Most Common letter in a string

By : Jeton Pllana
Date : November 17 2020, 04:28 AM
may help you . Completing an exercise to find the most common letter in a string, excluding punctuation and the result should be in lowercase. So in the example "HHHHello World!!!!!!!!!!" the result should be "h".
code :
text = input('Insert String: ')

from string import punctuation
from collections import Counter
def mwl(text):
    st = set(punctuation)
    # remove all punctuation and make every letter lowercase
    filtered = (ch.lower() for ch in text if ch not in st)
    # make counter dict from remaining letters and return the most common
    return Counter(filtered).most_common()[0][0]
from string import punctuation
from collections import Counter
def mwl(text):
    text = text.lower().translate(str.maketrans(" "*len(punctuation),punctuation))
    return Counter(text).most_common()[0][0]
def mwl(text):
    import string
    import collections
    text = text.lower() 
    for l in string.punctuation:
        for x in text:
            if x == l:
                text = text.replace(x,'')
    collist=collections.Counter(text).most_common(1)
    print(collist[0][0])
for l in string.punctuation:
     if l in text:
        text = text.replace(l,'')


Share : facebook icon twitter icon
Removing common letter from a string iOS

Removing common letter from a string iOS


By : Rob Robinson
Date : March 29 2020, 07:55 AM
Any of those help From your example I assume that everything is hyphen separated, so, you can use componentsSeparatedByString: to split into an array of words. Then, depending on whether you want to maintain order or not you can create a set from the array to remove the duplicates or you can iterate over the array and add each item to a new array if the destination array doesn't already contain the string. Then you can use componentsJoinedByString: to get back to a string again.
Why won't the final string show correct output when concatenate 2 string to a third one letter by letter?

Why won't the final string show correct output when concatenate 2 string to a third one letter by letter?


By : user2893776
Date : March 29 2020, 07:55 AM
I hope this helps you . Accessing the s3 string using the operator [i] with i bigger than the current length is undefined behavior.
You could try making s3 big enough (e.g. fill with spaces) before your loops. Note that your current implementation only works if both strings are the same length.
How to write a method that finds the most common letter in a string?

How to write a method that finds the most common letter in a string?


By : merryland
Date : March 29 2020, 07:55 AM
To fix the issue you can do This is the question prompt: , I suggest you use a counting hash:
code :
str = "The quick brown dog jumped over the lazy fox."

str.downcase.gsub(/[^a-z]/,'').
             each_char.
             with_object(Hash.new(0)) { |c,h| h[c] += 1 }.
             max_by(&:last)
   #=> ["e",4]
s = str.downcase.gsub(/[^a-z]/,'')
  #=> "thequickbrowndogjumpedoverthelazyfox"
enum0 = s.each_char
  #=> #<Enumerator: "thequickbrowndogjumpedoverthelazyfox":each_char>  
enum1 = enum0.with_object(Hash.new(0))
  #=> #<Enumerator: #<Enumerator:
  #    "thequickbrowndogjumpedoverthelazyfox":each_char>:with_object({})> 
enum1.to_a
  #=> [["t", {}], ["h", {}], ["e", {}], ["q", {}],..., ["x", {}]] 
c,h = enum1.next
  #=> ["t", {}] 
c #=> "t" 
h #=> {} 
h[c] += 1
  #=> h[c] = h[c] + 1
  #=> h["t"] = h["t"] + 1
  #=> h["t"] = 0 + 1 #=> 1
h #=> {"t"=>1}
c,h = enum1.next
  #=> ["h", {"t"=>1}] 
h[c] += 1
  #=> 1 
h #=> {"t"=>1, "h"=>1} 
Return a string with the first letter, then the letter one index from the first, then the letter 2 indices from the seco

Return a string with the first letter, then the letter one index from the first, then the letter 2 indices from the seco


By : devsda0
Date : March 29 2020, 07:55 AM
this will help You can do it with the following simple while-loop, maintaining index and increment:
code :
string = "0123456789ABCDEFG"
new_string, ind, inc = "", 0, 0
while ind < len(string):
    new_string += string[ind]
    inc += 1
    ind += inc
new_string
# '0136AF'
from itertools import accumulate, count, takewhile

string = "0123456789ABCDEFG"
''.join(string[i] for i in takewhile(lambda x: x < len(string), accumulate(count())))
# '0136AF'
How to check first letter of one string with last letter of another string inside of same char array

How to check first letter of one string with last letter of another string inside of same char array


By : user2058787
Date : March 29 2020, 07:55 AM
will help you Well, first of all think of the way you can reach that answer.
If you only need to know if they can or can not be arranged and you do not have to do so your self you can use an empty array of int array[26] for each letter a-z.
code :
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MINASCII 97
#define LETTERS 26
void UpdateArray(char letter, int* arr)
{

  if(arr[letter - MINASCII] == 0)
  {
      ++arr[letter - MINASCII];
  }
  else
  {
     --arr[letter - MINASCII];/*for each second time same letter is seen reduce back to zero */
  }
}
int canArrangewords(int wordNum, char* wordArr[])
{
  int arr[LETTERS] = {0};
  int i = 0;
  int count = 0 ;
  char first;
  char last;
  char* string;
  for (i= 0; i< wordNum; ++i)
  {
     string = wordArr[i];
     first = string[0];
     last = string[strlen(string)-1];
     UpdateArray(first, &arr[0]);
     UpdateArray(last, &arr[0]);
 }

  for(i = 0; i< LETTERS; ++i)
  {
    count+=arr[i];
  }
  if(count == 2 || count == 0)/*either once each or twice -see word1 example in main*/
  {
    return 1;
  }
  return -1;
}


int main()
{
  int i = 0;
  char* words[] = {"pot", "ten", "nice", "eye"};
  char* words1[] = {"pot", "ten", "nip"};
  char* words2[] = {"fox", "owl", "pond"};
  i = canArrangewords(4,words);
  printf("%d\n", i);
  i = canArrangewords(3,words1);
  printf("%d\n", i);
  i = canArrangewords(3,words2);
  printf("%d\n", i);
  return 0;
 }
Related Posts Related Posts :
  • Remove commas in a string, surrounded by a comma and double quotes / Python
  • How to chain Django querysets preserving individual order
  • Comparison with Python
  • How to find backlinks in a website with python
  • Return new instance of subclass when using methods inherited from parent class in Python
  • Which function in django.contrib.auth creates the default model permissions?
  • Formatting text in tabular form with Python
  • How to determine the first day of a month in Python
  • Error while converting date to timestamp in python
  • Python string iterations
  • Is there any file number limitation when you select multiple files with wxFileDialog?
  • Errors with Matplotlib when making an executable with Py2exe (Python)
  • Django Haystack - Indexing single field
  • Go Pro Hero 3 - Streaming video over wifi
  • Appending a column in .csv with Python/Pandas
  • How to change my result directory in Robot framework using RIDE?
  • problem with using pandas to manipulate a big text file in python
  • python-magic module' object has no attribute 'open'
  • Where goes wrong for this High Pass Filter in Python?
  • Why inserting keys in order into a python dict is faster than doint it unordered
  • flann index saving in python
  • Create new instance of list or dictionary without class
  • How can I easily convert FORTRAN code to Python code (real code, not wrappers)
  • Address of lambda function in python
  • Python adding space between characters in string. Most efficient way
  • python http server, multiple simultaneous requests
  • Disguising username & password on distributed python scripts
  • Post GraphQL mutation with Python Requests
  • Why doesnt pandas create an excel file?
  • Rolling comparison between a value and a past window, with percentile/quantile
  • How to avoid repetitive code when defining a new type in python with signature verification
  • How to configure uWSGI in order to debug with pdb (--honour-stdin configuration issue)
  • In Python, how do you execute objects that are functions from a list?
  • Python- Variable Won't Subtract?
  • Processing Power In Python
  • Python 2.7.2 - Cannot import name _random or random from sys
  • Why doesn't the Python sorted function take keyword order instead of reverse?
  • Make a function redirect to other functions depending on a variable
  • get_absolute_url in django-categories
  • Monitoring non-Celery background task with New Relic in Python
  • Feature selection with LinearSVC
  • LSTM - Predicting the same constant values after a while
  • Test the length of elements in a list
  • Django: render radiobutton with 3 columns, cost column must change according to size & quantity selected
  • Python class attributes vs global variable
  • sys.stdout.writelines("hello") and sys.stdout.write("hello")
  • is ndarray faster than recarray access?
  • Python - search through directory trees, rename certain files
  • GAE: How to build a query where a string begins with a value
  • TypeError: __init__() takes at least 2 arguments (1 given)
  • Overriding and customizing "django.contrib.auth.views.login"
  • Django : Redirect to a particular page after login
  • Python search and copy files in directory
  • pretty printing numpy ndarrays using unicode characters
  • Frequent pattern mining in Python
  • How can I make a set of functions that can be used synchronously as well as asynchronously?
  • Convert one dice roll to two dice roll
  • count occourrence in a list
  • Writing an If condition to filter out the first word
  • to read file and compare column in python
  • shadow
    Privacy Policy - Terms - Contact Us © ourworld-yourmove.org