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Understanding PHP Object Type Comparisons


Understanding PHP Object Type Comparisons

By : Dinesha Gallage
Date : November 17 2020, 01:00 AM
should help you out Two objects of different type can never be equal. PHP does not let an object decide itself if it's equal to another object, as java does with the equal-method.
http://php.net/manual/en/language.oop5.object-comparison.php
code :
$this->assertsTrue( $result->equals(Money::dollar(7)) );


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Understanding bitwise comparisons between non-boolean parameters

Understanding bitwise comparisons between non-boolean parameters


By : Charlie S
Date : March 29 2020, 07:55 AM
With these it helps I'm working with some old code, trying to improve it, and I came across the following, which I am having trouble understanding:
code :
controlToUpdate.Font.Style & FontStyle.Bold
controlToUpdate.Font.Style ^ (controlToUpdate.Font.Style & FontStyle.Bold)
controlToUpdate.Font.Style & ~FontStyle.Bold
000....000001
111...1111110
Understanding iterable types in comparisons

Understanding iterable types in comparisons


By : madhuri
Date : March 29 2020, 07:55 AM
this one helps. The basic reason why id(reversed(a) == id(reversed(a) returns True , whereas reversed(a) == reversed(a) returns False , can be seen from the below example using custom classes -
code :
>>> class CA:
...     def __del__(self):
...             print('deleted', self)
...     def __init__(self):
...             print('inited', self)
...
>>> CA() == CA()
inited <__main__.CA object at 0x021B8050>
inited <__main__.CA object at 0x021B8110>
deleted <__main__.CA object at 0x021B8050>
deleted <__main__.CA object at 0x021B8110>
False
>>> id(CA()) == id(CA())
inited <__main__.CA object at 0x021B80F0>
deleted <__main__.CA object at 0x021B80F0>
inited <__main__.CA object at 0x021B80F0>
deleted <__main__.CA object at 0x021B80F0>
True
>>> a = [1,2,3]
>>> b = [4,5,6]
>>> id(reversed(a)) == id(reversed(b))
True
all(x==y for x,y in zip(aiterator,biterator))
from itertools import izip
all(x==y for x,y in izip(aiterator,biterator))
>>> a = [1,2,3]
>>> b = [4,5,6]
>>> all(x==y for x,y in zip(reversed(a),reversed(b)))
False
>>> all(x==y for x,y in zip(reversed(a),reversed(a)))
True
Trouble understanding Swift Tuple comparisons

Trouble understanding Swift Tuple comparisons


By : 姜世丰
Date : March 29 2020, 07:55 AM
I wish this help you This is a multi-field sort.
First sorting is done by the first entry. Ties are decided by the second entry (and so forth if the tuple is longer).
Is there a concept name for a regular type for which comparisons doesn't compare the full object state?

Is there a concept name for a regular type for which comparisons doesn't compare the full object state?


By : randomPersonGuy
Date : March 29 2020, 07:55 AM
hope this fix your issue MyFlag is not EqualityComparable, since == returns true for objects with distinct values. The definition of EqualityComparable in §3.3 includes axiom { a == b <=> eq(a, b); }.
Informally, eq is meant to represent equality of what we would consider to be the value of an object regardless of the existence of an == for that object's type. This isn't strictly the same thing as representational equality, since (a) different representations can be considered equal (e.g., -0.0 == 0.0), and (b) there can be insignificant state in representations (colloquially "padding").
Understanding estimator.evaluate and outputting comparisons

Understanding estimator.evaluate and outputting comparisons


By : Kaushik Pal
Date : March 29 2020, 07:55 AM
this one helps. So in the event that someone reads the question above, and understands what I was trying to do (view the output of predictions), I have a solution.
The solution is to utilize the .predict() method.
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